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melomori [17]
4 years ago
10

A 1.10 mol sample of krypton gas is collected at a pressure of 427 mmHg and a temperature of 6.0°C. The volume of the sample is

? L.
Chemistry
1 answer:
Aleksandr [31]4 years ago
6 0

Answer:

Volume = 44.96L

Explanation:

p = 427mmHg = 0.56atm

R = 0.08206

T 6°C = 279k

V = ?

n = 1.10 mol

using ideal gas equation

pv=nRT

0.56 x V = 1.10 x 0.08206 x 279

0.56 x V = 25.18

V = 25.18/0.56

V = 44.96L

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Match each term to its description. Match Term Definition Excess reactant A) Reactant that can produce more of the product Limit
faust18 [17]

Answer:

Explanation:

A) Reactant that can produce more of the product

Excess reactant:

In a given reaction, the reactant that is in excess supply is the excess reactant. If the amount of the excess reactant is match, more of the product will be produced.

B) Reactant that can produce a lesser amount of the product

Limiting reactant

The limiting reactant restricts the progress of the reaction. It determines the amount of product that can be formed.

C) Amount of product predicted to be produced by the given reactants

Theoretical yield

For a given amount of reactants, the theoretical yield determines the amount of products that can be produced.

5 0
3 years ago
Pls help one chemistry question :/
jolli1 [7]

Answer:

the anserw should be 665KJ

8 0
2 years ago
Elements that have five electrons in the highest-energy p sublevel in their ground state are called what?
wolverine [178]
Elements that have six electrons in the highest-energy p sublevel in their ground state are called the noble gases or inert gases. The six noble gases that occur naturally are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and the radioactive radon (Rn).
5 0
3 years ago
Which element will gain only one electron during a chemical reaction?
pashok25 [27]

Answer:

  1. nitrogen

Explanation:

SANA PO MAKATULONG PO YUNG SAGOT NA BINIGAY KO

8 0
3 years ago
4. Al2O3 (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H20(1) Find the mass of AlCl3 that is produced when 10.0 grams of Al2O3 react with 10.
slava [35]

Answer:

Are produced 12,1 g of AlCl₃ and 5,33 g of Al₂O₃ are left over

Explanation:

For the reaction:

Al₂O₃ (s) + 6 HCl (aq) → 2AlCl₃ (aq) + 3H₂0(l)

10,0g of Al₂O₃ are:

10,0g ₓ\frac{1mol}{102g} = <em>0,0980 moles</em>

And 10,0g of HCl are:

10,0 gₓ\frac{1mol}{36,5g} = <em>0,274 moles</em>

<em />

For a total reaction of 0,274 moles of HCl you need:

0,274×\frac{1molesAl_{2}O_3}{6 mole HCl} = <em>0,0457 moles of Al₂O₃</em>

Thus, limiting reactant is HCl

The grams produced of AlCl₃ are:

0,274 moles HCl ×\frac{2 moles AlCl_{3}}{6 moles HCl} × 133\frac{g}{mol} = <em>12,1 g of AlCl₃</em>

<em />

The moles of Al₂O₃ that don't react are:

0,0980 moles - 0,0457 moles =<em> </em>0,0523 moles

And its mass is:

0,0523 molesₓ\frac{102g}{1mol} = <em>5,33 g of Al₂O₃ </em>

<em />

I hope it helps!

7 0
3 years ago
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