Answer:
The maximum power density in the reactor is 37.562 KW/L.
Explanation:
Given that,
Height = 10 ft = 3.048 m
Diameter = 10 ft = 3.048 m
Flux = 1.5
Power = 835 MW
We need to calculate the volume of cylinder
Using formula of volume

Put the value into the formula


We need to calculate the maximum power density in the reactor
Using formula of power density

Where, P = power density
E = energy
V = volume
Put the value into the formula


Hence, The maximum power density in the reactor is 37.562 KW/L.
I think the answer is A I’m
Not sure tho
Purpose: experiments will use it to measure the straight-line accelerated motion of a human hand. The displacement data will be measured and velocity and acceleration will be calculated, run the ticker tape under the guides on the timer and under the carbon circle.Hope this helps! ; )