1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liq [111]
2 years ago
6

A rectangular block has the following dimensions: 3.21 dm, 5.83 cm, and 1.84 in. The block has a mass of 1.94 kg. What is the de

nsity of the blocking/mL? 1 in = 2.54 cm​
Chemistry
1 answer:
spin [16.1K]2 years ago
4 0

The density of the rectangular block in g/mL is 7.0.

<u>Given the following data:</u>

  • Mass of block = 22.8 gra1.94 kg
  • Length of block = 3.21 cm
  • Width of block = 5.83 cm
  • Height of block = 1.84 in.

To find the density of the block in g/mL:

First of all, we would determine the volume of the rectangular block by using the following formula:

Volume = length × width × height

<u>Conversion:</u>

1 in = 2.54 cm​

5.83 in = X cm

Cross-multiplying, we have:

X = 2.54(5.83)\\\\X = 14.81 \; cm

Volume = 3.21 × 5.83 × 14.81

Volume = 277.16 cubic centimeters.

<u>Note</u>: Milliliter (mL) is the same as cubic centimeters.

1000 grams = 1 kg

Y grams = 1.94 kg

Cross-multiplying, we have:

Y = 1940 grams

Now, we can find the density:

Density = \frac{Mass}{Volume}\\\\Density = \frac{1940}{277.16}

<em>Density </em><em>= 7</em><em>.0 g/mL</em>

Therefore, the density of the rectangular block in g/mL is 7.0.

Read more: brainly.com/question/18320053

You might be interested in
Metallic elements can be recovered from ores that are oxides, carbonates, halides, or sulfides. Give an example of each type.
vredina [299]

Metallic elements which can be recovered from ores that are oxides, carbonates, halides, or sulfides are iron, zinc, silver and lead respectively.

Ores which is deposited in earth's crust which contain minerals and metals. Metals can be obtained economically and sold commercially.

<h3>How metals obtained from sulphide or carbonate ore? </h3>

As we get to know that it is easy to obtain metals from their oxides. So, firstly ores which is found in the form of carbonates and sulphide are converted into their oxides by using the process of calcination and roasting.

The metals which is in the middle of the activity series are moderately reactive. These metals are found in the crust of the earth is mainly found as oxides, sulphides, or carbonates.

A metal which can occur in the form of sulphide ore is lead.

A metal which can occur in the form of oxide ore is iron.

A metal which can occur in the form of carbonate ore is zinc.

A metal which can occur in the form of halides ore is silver.

Thus, we concluded that the metallic elements which can be recovered from ores that are oxides, carbonates, halides, or sulfides are iron, zinc, silver and lead respectively.

learn more about ore:

brainly.com/question/10306443

#SPJ4

6 0
1 year ago
Please Help Me Balance The equation!! will mark brainliest
Delvig [45]

Answer:

XCl2 + 2 AgNO3 = X(NO3)2 + 2 AgCl

Explanation:

i ran this through a calculator

8 0
2 years ago
Read 2 more answers
Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r
MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0
3 years ago
Read 2 more answers
Hi please Help me in my hww
omeli [17]
1) is C because the arrows are pointing in so that means to squeeze
3) is A as the picture shows the dropper
8 0
3 years ago
How many grams of H, are needed to react with 2.75 g of N,?
Elena-2011 [213]

Answer:

0.6 grams of hydrogen are needed to react with 2.75 g of nitrogen.

Explanation:

When hydrogen and nitrogen react they form ammonia.

Chemical equation:

N₂ + 3H₂ → 2NH₃

Given mass of nitrogen = 2.75 g

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 2.75 g / 28 g/mol

Number of moles = 0.098 mol

Now we will compare the moles of nitrogen with hydrogen from balance chemical equation:

                   N₂             :          H₂

                    1               :           3

                   0.098       :        3×0.098 = 0.3 mol

Mass of hydrogen:

Mass = number of moles × molar mass

Mass = 0.3 mol × 2 g/mol

Mass = 0.6 g

6 0
3 years ago
Other questions:
  • A 2.00 kg piece of lead at 40.0°C is placed in a very large quantity of water at 10.0°C,and thermal equilibrium is eventually re
    9·1 answer
  • A homeogeneous mixture or solution consist of
    9·2 answers
  • This type of chemical bond forms when electrons are either gained or lost by an atom.
    6·1 answer
  • The thermometer in the picture reads, "19.9 degrees Celsius".
    9·1 answer
  • Bromination occurs on alkene functional groups, but not on alkenes found within aromatic functional groups, such as the phenyl r
    12·1 answer
  • What is the oxidation number of P in PF6−?
    10·1 answer
  • Answer this please thank you
    6·1 answer
  • Differences between hilum and micropyle​
    11·1 answer
  • Which type of reaction is <br> NaOH + KNO3 NaNO3 + KOH<br> --&gt;&gt;
    9·1 answer
  • Phosphorus trichloride (PC) is used as a reactant in the production of many other chemicals that contain phosphorus, including p
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!