Question

A rectangular block has the following dimensions: 3.21 dm, 5.83 cm, and 1.84 in. The block has a mass of 1.94 kg. What is the density of the blocking/mL? 1 in = 2.54 cm​

Answer 1

The density of the rectangular block in g/mL is 7.0.

Given the following data:

• Mass of block = 22.8 gra1.94 kg

• Length of block = 3.21 cm

• Width of block = 5.83 cm

• Height of block = 1.84 in.

To find the density of the block in g/mL:

First of all, we would determine the volume of the rectangular block by using the following formula:

$Volume = length$ × $width$ × $height$

Conversion:

1 in = 2.54 cm​

5.83 in = X cm

Cross-multiplying, we have:

$X = 2.54(5.83)\\\\X = 14.81 \; cm$

$Volume = 3.21$ × $5.83$ × $14.81$

Volume = 277.16 cubic centimeters.

Note: Milliliter (mL) is the same as cubic centimeters.

1000 grams = 1 kg

Y grams = 1.94 kg

Cross-multiplying, we have:

Y = 1940 grams

Now, we can find the density:

$Density = \frac{Mass}{Volume}\\\\Density = \frac{1940}{277.16}$

Density = 7.0 g/mL

Therefore, the density of the rectangular block in g/mL is 7.0.

Read more: brainly.com/question/18320053