Answer:
the answer of your question is yes
Answer:
no i do not sorry for you
1)
Volume = 19 / 1000 = 0.019 L
n = M * V
n = 0.100 * 0.019
n = 0.0019 moles
__________________________
2)
M₁ * V₁ = M₂* V₂
5.0 * V₁ = 1.0 * 152
5.0 V₁ = 152
V₁ = 152 / 5.0
V₁ = 30.4 mL
______________________________________
<span>hope this helps!</span>
<span>Dmitri Mendeleev thats the answer</span>
Answer:
5 g
Explanation:
From the question, we have,
Molarity of FeIII solution= 0.245 M
Volume of solution = 125 ml
From
number of moles= concentration × volume
We have;
Number of moles= 0.245 M × 125/1000
Number of moles = 0.031 moles
Molar mass of Fe III = 162.5g/moles
Mass of iron III = number of moles× molar mass = 0.031 × 162.5= 5 g
n
