Answer:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Explanation:
AlF₃ + Li₂O —> Al₂O₃ + LiF
The above equation can be balanced as follow:
AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 2 before AlF₃ as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 6 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 6 before LiF as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + 6LiF
There are 2 atoms of Li on the left side and 6 atoms on the right side. It can be balance by writing 3 before Li₂O as shown below:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Thus, the equation is balanced..!
Answer:
9/10hr
Explanation:
From the question given:
Carla was able to burn 250 calories by running for one-half (1/2)hr.
Therefore, Carla will burn 450calories by running for = (450x1/2) /250 = 225/250 = 9/10hr
Answer: The metals are to the left of the line (except for hydrogen, which is a nonmetal), the nonmetals are to the right of the line, and the elements immediately adjacent to the line are the metalloids.
Explanation:
When elements combine to form compounds, there are two major types of bonding that can result.
Answer:
(1) 0.035 × 10²³
Explanation:
Step 1: Calculate the mass of Fe in 100 g of Haemoglobin
Haemoglobin contains 0.33% Fe, that is, there are 0.33 g of Fe per 100 grams of Haemoglobin.
100 g Hb × 0.33 g Fe/100 g Hb = 0.33 g Fe
Step 2: Convert 0.33 g of Fe to moles
We will use the molar mass of Fe (55.85 g/mol).
0.33 g × 1 mol/55.85 g = 5.9 × 10⁻³ mol
Step 3: Convert 5.9 × 10⁻³ moles of Fe to atoms
We will use Avogadro's number.
5.9 × 10⁻³ mol × 6.02 × 10²³ atoms/1 mol = 3.5 × 10²¹ atoms (= 0.035 × 10²³)
Answer:
The red litmus turns to blue
Explanation:
Hope it helps