Where’s the question or equation
I think the statement is false. Natural elements do reflect light. Almost everything in this world reflect light. Reflection<span> is when </span>light<span> bounces off an object. Hope this answers the question. Have a nice day.</span>
A contains 38.5 g of tin for each 12.3 g of fluorine:
<span>mole ratio: </span>
<span>(38.5 g)/(118.71 g/mol):(12.3 g)/(18.998 g/mol) = 0.324:0.647 = 1:2 ⇒ SnF₂ </span>
<span>B contains 56.5 g of tin for each 36.2 g of fluorine: </span>
<span>mole ratio: </span>
<span>(56.5 g)/(118.71 g/mol):(36.2 g)/(18.998 g/mol) = 0.476:1.905 = 1:4 ⇒ SnF₄
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Answer:
By using the techniques of archeology.
Explanation:
Students recover an individual's remains from a surface grave by using the techniques of archeology field to scrape away the layers of soil from that remains in a way that the remains can't be damaged. If they find the remains within 10 centimeters of digging, they can dig down further in order to dig out all the remains safely. The instruments of archeology field are used because they are light and can be used to dig out fossils of ancient organisms.
Answer:
Average atomic mass = 14.0067 amu.
Explanation:
Given data:
Abundance of 1st isotope = 99.63%
Atomic mass of 1st isotope = 14.003 amu
Abundance of 2nd isotope = 0.37%
Atomic mass of 2nd isotope = 15.000 amu
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (99.63×14.003)+(0.37×15.000) /100
Average atomic mass = 1395.119 + 5.55 / 100
Average atomic mass = 1400.67 / 100
Average atomic mass = 14.0067 amu.
