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luda_lava [24]
3 years ago
11

For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.

Chemistry
1 answer:
vichka [17]3 years ago
6 0

Answer:

\Delta G =-103.95kJ

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

\Delta G =\Delta H-T\Delta S

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ

Best regards!

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