Answer:
how about you just put whats on your mind and continue on
Explanation:
no need to ask this question just answer it and move on or you will lose your sanity trying to figure this out
Answer:
8.66 g of Al₂O₃ will be produced
Explanation:
4Al (s) + 3O₂ (g) → 2Al₂O₃ (s)
This is the reaction.
Problem statement says, that the O₂ is in excess, so the limiting reactant is the Al. Let's determine the moles we used.
4.6 g / 26.98 g/mol = 0.170 moles
Ratio is 4:2.
4 moles of aluminum can produce 2 moles of Al₂O₃
0.170 moles of Al, may produce (0.170 .2)/ 4 = 0.085 moles
Let's convert the moles of Al₂O₃ to mass.
0.085 mol . 101.96 g/mol = 8.66 g
Answer:
1.41 g of H₂O
Solution:
The equation for given reaction is as follow,
Cu₂O + H₂ → 2 Cu + H₂O
According to equation,
127 g (2 mole) Cu is produced along with = 18 g (1 mole) of H₂O
So,
10 g Cu produced will generate = X g of H₂O
Solving for X,
X = (18 g × 10 g) ÷ 127 g
X = 1.41 g of H₂O
They expect the Universe to continue expanding. Right now, the evidence is that the expansion is speeding up. They also expect entropy to continue increasing, so in the distant future, there will not be any free energy left to support life, for example.
