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yulyashka [42]
3 years ago
6

Require a little help with this please and thank you

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
4 0

Answer:

201.06 is the area

Step-by-step explanation:

With the diameter being 16cm

The radius would be 8cm, with that information using the formula

A = π x r^2

I got 201.06 cm as the area

The circumference is 50.27 cm

I hope this helps, if not sorry

natka813 [3]3 years ago
4 0
<h3><u>Solution</u><u>:</u></h3>
  • Here, the length of the side of the square is 16 cm.
  • Here, the circle touches the square.
  • So, the diameter of the circle = 16 cm
  • Therefore, radius of the circle = Diameter of the circle ÷ 2

= 16 cm ÷ 2

= 8 cm

  • Area of a circle = πr^2 where r is the radius of the circle
  • Therefore, area of the circle

=  \pi \times 8cm \times 8cm\\  = 3.14  \times 8cm \times 8cm \\  =  200.96 \: square cm

<h3><u>Answer</u><u>:</u></h3>

The area of the circle is 200.96 square cm.

(I have taken π as 3.14, you may take 22/7 but it will be a very long answer. So I prefer you to take π as 3.14)

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4) The limit does not exist.

General Formulas and Concepts:

<u>Calculus</u>

Limits

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<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}

<u>Step 2: Find Left-Side Limit</u>

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<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Right-Side Limit]:                                                     \displaystyle \lim_{x \to 5^+} x + 3
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8

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