Answer: The process of liquid turning into the gas phase.
Explanation:
When liquid molecules collide, they transfer energy to one another.
Gamma rays because it is a form of electromagnetic radiation. It has zero mass and no charge.
Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:
![W_b = m_bg = \\ \\ W_b = (0.730 \ kg) ( 9.80 \ m/s^2) \\ \\ W_b = 7.154 \ N](https://tex.z-dn.net/?f=W_b%20%3D%20m_bg%20%3D%20%20%5C%5C%20%5C%5C%20%20W_b%20%3D%20%280.730%20%5C%20%20kg%29%20%28%209.80%20%5C%20m%2Fs%5E2%29%20%5C%5C%20%5C%5C%20W_b%20%3D%207.154%20%5C%20N)
The mass of the water accumulated in the bucket after 3.20s is:
![m_w= (0.20 \ L/s) ( 3.20)s](https://tex.z-dn.net/?f=m_w%3D%20%280.20%20%5C%20L%2Fs%29%20%28%203.20%29s)
![m _w=0.64 \ kg](https://tex.z-dn.net/?f=m%20_w%3D0.64%20%5C%20kg)
To determine the weight of the water accumulated in the bucket, we have:
![W_w = m_w g](https://tex.z-dn.net/?f=W_w%20%3D%20m_w%20g)
![W_w = ( 0.64 \ kg )(9.80\ m \ /s^2)](https://tex.z-dn.net/?f=W_w%20%3D%20%28%200.64%20%20%5C%20kg%20%29%289.80%5C%20%20m%20%20%5C%20%20%2Fs%5E2%29)
![W_w = 6.272 \ N](https://tex.z-dn.net/?f=W_w%20%3D%206.272%20%5C%20N)
For the speed of the water before hitting the bucket; we have:
![v = \sqrt{2gh}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2gh%7D)
![v = \sqrt{2*9.80 \ m/s^2 * 3.60 \ m}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2%2A9.80%20%5C%20m%2Fs%5E2%20%2A%203.60%20%5C%20m%7D)
v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:
![F = v ( \dfrac {dm}{dt} )](https://tex.z-dn.net/?f=F%20%3D%20v%20%28%20%5Cdfrac%20%7Bdm%7D%7Bdt%7D%20%29)
![F = (8.4 \ m/s)( 0.200 \ L/s)](https://tex.z-dn.net/?f=F%20%3D%20%288.4%20%5C%20m%2Fs%29%28%200.200%20%5C%20L%2Fs%29)
F = 1.68 N
Finally, the reading scale is:
= 7.154 N + 6.272 N + 1.68 N
= 15.106 N
Answer:
100 micro-ampere
Explanation:
The sensitivity of an ammeter is the current required for the ammeter to reach its maximum reading or to cause maximum deflection of the ammeter.
As the relative amount of current required to cause maximum deflection of an ammeter is lesser, the sensitivity of the ammeter is said to be higher or the ammeter is said to be more sensitive
Therefore, given that the maximum reading on the given microammeter is 100 μA, the current required to cause the maximum deflection an thus the sensitivity of the ammeter is 100 micro-ampere.