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3 years ago

As the atomic number _____(Increases/Decreases) within a period, the atomic radius _(Increases/Decreases).

Chemistry

1 answer:

Alex777 [14]3 years ago

3 0

Answer:

Atomic radius is the distance from the atom's nucleus to the outer edge of the electron cloud. In general, atomic radius decreases across a period and increases down a group.

Explanation: you should mark me brainliest

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2. The volume of a rock is 5 cm' and its mass is 50 g. Find the density.<br> pls help :)

Vladimir [108]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume}\\$

From the question we have

$density = \frac{50}{5} = 10 \\$

We have the final answer as

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4 years ago

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Mixing Strong Acids with Strong Bases What is the pH of the solution that results from mixing 8.00 mL of 0.030 M perchloric acid

garik1379 [7]

Answer: PH= 1.4

Explanation:

n(mole)= concentration(c)× volume(v)

n(HClO4) = 0.08 ×0.03

n(HClO4)= 0.0024 mole

n(Ba(OH)2) = 0.28 × 0.05

n(Ba(OH)2) = 0.014

2HClO4 + Ba(OH)2.....>Ba(ClO4)2 + 2H2O.

Hence, the limiting reagent is perchloric acid. According to the reaction:

0.0024 HClO4 req 1/2× 0.0024 of Ba(OH)2.

n(Ba(OH) reacted= 0.0012

Excess n(Ba(OH)2) = 0.014-0.0012

Excess n(Ba(OH)2) = 0.0128

Conc(Ba(OH)2) unreacted = 0.0128/.32 (vol. of mix is 32ml)

= 0.04M = [H+]

PH = -log[0.04] = 1.397

PH= 1.4

6 0

3 years ago

If 0.15 mol of I2 vapor can effuses through an opening in a heated vessel in 36 sec, how long will it take 0.15 mol of Cl2 to ef

marysya [2.9K]

<u>Answer:</u> The amount of time required by chlorine gas to effuse is 19 seconds.

<u>Explanation:</u>

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

$\text{Rate}=\frac{n}{t}$

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So,

$\left(\frac{\frac{n_{Cl_2}}{t_{Cl_2}}}{\frac{n_{I_2}}{t_{I_2}}}\right)=\sqrt{\frac{M_{I_2}}{M_{Cl_2}}}$

We are given:

Moles of iodine gas = 0.15 moles

Moles of chlorine gas = 0.15 moles

Time taken by iodine gas = 36 seconds

Molar mass of iodine gas = 254 g/mol

Molar mass of chlorine gas = 71 g/mol

Putting values in above equation, we get:

$\left(\frac{\frac{0.15}{t_{Cl_2}}}{\frac{0.15}{36}}\right)=\sqrt{\frac{254}{71}}\\\\\frac{0.15}{t_{Cl_2}}\times \frac{36}{0.15}=1.89\\\\t=19s$

Hence, the amount of time required by chlorine gas to effuse is 19 seconds.

6 0

3 years ago

As the atomic number ___________(Increases/Decreases) within a period, the atomic radius _______(Increases/Decreases).

As the atomic number _____(Increases/Decreases) within a period, the atomic radius _(Increases/Decreases).