uhmm, white.
Explanation:
you'll basically look like blind ig
In Lewis dot structures, you draw the atom in the center and then surround the atom with its valence electrons. The Lewis structure for O is as shown in the attached diagram.
<h3>What is the Lewis structure of O ?</h3>
Lewis Structure of an atom of oxygen contains 6 electrons in the valence shell. Four valence electrons exist in lone pairs. It implies that oxygen atom must participate in two single bonds or one double bond in order to have an octet configuration.
A simplified representation of the valence shell electrons in a molecule is called Lewis Structure. It shows how electrons are arranged around individual atoms in the molecule.
To know more about Lewis structure, refer
brainly.com/question/1525249
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Answer: 0.0 grams
Explanation:
To calculate the moles, we use the equation:

a) moles of butane

b) moles of oxygen


According to stoichiometry :
2 moles of butane require 13 moles of 
Thus 0.09 moles of butane will require =
of 
Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.
Thus all the butane will be consumed and 0.0 grams of butane will be left.
Answer:- There are
moles.
Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is
and it's molar mass is 294.31 grams per mole.
mg are converted to grams and then the grams are converted to moles as:

=
moles of aspartame
So, there would be
moles of aspartame in 1.00 mg of it.