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Nataliya [291]
2 years ago
15

Help help me help help please help help me help help please help help me help help

Mathematics
1 answer:
goblinko [34]2 years ago
5 0

Answer:

mega mind<3<3<3<3<3<3<×<×<

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Assume you purchased a car for $2,300 and sold it one week later for $3,100. How much did your net worth change, if at all?
Natali5045456 [20]

Answer:

My net wroth would have changed by $800

Step-by-step explanation:

Because $3,100 - $2,300 = $800

4 0
3 years ago
Identify the perfect cube contained as a factor in 54
erastova [34]

Answer:

27.

Step-by-step explanation:

54 = 2 * 3 * 3 * 3.

3 occurs 3 times so the perfect cube is 27.

8 0
3 years ago
Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex
bagirrra123 [75]

Answer:

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

\hat p=0.021 estimated proportion of interest

p_o=0.012 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:  

Null hypothesis:p \leq 0.012  

Alternative hypothesis:p > 0.012  

When we conduct a proportion test we need to use the z statisitic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0
3 years ago
The midpoint of AB is M(4, -1). If the coordinates of A are (2,5), what are the
ozzi

Answer:

(6,-7)

Step-by-step explanation:

take b as x2,y2

then apply mid point formula

x=(x1+x2)/2

y=(y1+y2)/2

8 0
3 years ago
Read 2 more answers
What is 80.89 divided by 8.425?
umka2103 [35]

Answer:

9.60 or 9.601 if you want the hundreths place

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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