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Archy [21]
2 years ago
14

How do you determine volume?

Mathematics
1 answer:
bulgar [2K]2 years ago
6 0

Answer:   V = πr 2 h

Step-by-step explanation:

To calculate the volume of a cylinder, you must know its height and the radius of the circular base (the distance from the center of the circle to its edge) at the top and bottom. The formula is V = πr 2 h, where V is the Volume, r is the radius of the circular base, h is the height, and π is the constant pi.

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These questions are really important for me to answer please guys help me
marysya [2.9K]

Answer:

\cos(41 = adj \div hyp

\cos(41)  =  \frac{y}{30cm}

y =  \cos(41)  \times 30

y=29.62017

4 0
3 years ago
PLEASE ANSWER THIS AND IF YOU DO YOU GET <br> 1. FOLLOW<br> 2. BRAINLIEST
snow_lady [41]
First: 0
Second: 0
Third: -5
Fourth: y=4x
7 0
3 years ago
This is Matrix for pre calc
gavmur [86]

The given system of equations in augmented matrix form is

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]

If you need to solve this, first get the matrix in RREF:

  • Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]

  • Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]

  • Add 164(row 3) to -91(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]

  • Multiply row 4 by 1/13080:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]

  • Add -153(row 4) to row 3:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]

  • Multiply row 3 by -1/91:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add 6(row 3) and -8(row 4) to row 2:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 2 by 1/5:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 1 by 1/3:

\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

So the solution to this system is (w,x,y,z)=(1,-2,4,-3).

6 0
3 years ago
HELP AS SOON AS POSSIBLE NEEDS ANSWERS ASAP
likoan [24]

Answer:

C. The mean will increase and ty e median will remain the same.

6 0
3 years ago
I NEED HELP ASAP <br><br> APEX!!!
igor_vitrenko [27]

The series will be:

4+16+64+.......+2^{50}

Hence, Option A is the right answer

Step-by-step explanation:

The series can be fount out by putting the values of i in the expression written with the summation

The expression is:

2^{2i}

while i = 1 to 25

Putting i = 1

2^{2(1)}\\= 2^2\\= 4

Putting i = 2

2^{2(2)}\\= 2^4\\= 16

Putting i = 3

2^{2(3)}\\= 2^6\\= 64

....

Putting i = 25

2^{2(25)}\\= 2^{50}

The series will be:

4+16+64+.......+2^{50}

Hence, Option A is the right answer

Keywords: Summation, Series

Learn more about summation at:

  • brainly.com/question/9381080
  • brainly.com/question/9532142

#LearnwithBrainly

6 0
3 years ago
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