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Diano4ka-milaya [45]
3 years ago
6

What is the leading hypothesis for venus’s lack of water?

Physics
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

Its water molecules were broken apart, and hydrogen was lost to space. What kind of gas is most affected by thermal escape? What causes the release of oxygen into Earth's atmosphere?

Explanation:

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Where does fission regularly occur and what kind of energy is produced?
Lapatulllka [165]
Your answer is C hope i helped
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3 0
4 years ago
Read 2 more answers
A convex mirror has a focal length of 15cm. If the object is 35cm from the mirror and is 2cm tall, what is the magnification? Ro
Verizon [17]

Answer:

The magnification is 0.3

Explanation:

Given:

The focal length of the convex mirror, f = 15 cm

for convex mirror f = -f = -15 cm

The distance of object, u = 35 cm

Height of the object, h = 2 cm

Now, using the mirror formula, we have

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

where, v is the distance of the image

on substituting the values, we get

\frac{1}{-15}=\frac{1}{35}+\frac{1}{v}

or

-\frac{1}{v}=\frac{1}{35}-\frac{1}{-15}

or

v = -10.5 cm

now, the magnification (m) is given as:

m = -\frac{v}{u}

on substituting the values, we get

m = -\frac{-10.5}{35}

or

m = 0.3

Hence, the magnification is 0.3

6 0
3 years ago
A cylinder has 500 cm3 of water. After a mass of 100 grams of sand is poured into the cylinder and all air bubbles are removed b
Nina [5.8K]

Answer: SG = 2.67

Specific gravity of the sand is 2.67

Explanation:

Specific gravity = density of material/density of water

Given;

Mass of sand m = 100g

Volume of sand = volume of water displaced

Vs = 537.5cm^3 - 500 cm^3

Vs = 37.5cm^3

Density of sand = m/Vs = 100g/37.5 cm^3

Ds = 2.67g/cm^3

Density of water Dw = 1.00 g/cm^3

Therefore, the specific gravity of sand is

SG = Ds/Dw

SG = (2.67g/cm^3)/(1.00g/cm^3)

SG = 2.67

Specific gravity of the sand is 2.67

3 0
3 years ago
Discuss how planck's hypothesis explain the observed blackbody spectrum.​
Rashid [163]

Answer:

Planck's radiation law, a mathematical relationship formulated in 1900 by German physicist Max Planck to explain the spectral-energy distribution of radiation emitted by a blackbody (a hypothetical body that completely absorbs all radiant energy falling upon it, reaches some equilibrium temperature, and then reemits

Explanation:

6 0
3 years ago
If an 0.6kg apple is dropped from 0.5m height onto a seesaw and flips up a 0.25kg kiwi. To what height does that kiwi reach. Ass
natita [175]

answer

Height at which kiwi reach=1.2m

Solution

In this question we have given

mass of apple, m_{a} =.6kg

mass of kiwi,m_{a} =.25kg

height from which apple is dropped,H_{a} =.5m

Let the height at which kiwi reached is H_{k}

here,

We will apply law of conservation of energy

it means,

potential energy of kiwi= potential energy of apple

m_{k}\times g\times H_{k}= m_{a}\times g\times H_{a}......(1)

here g is gravitational acceleration

put values of m_{k} , g, H_{k}, m_{a} and H_{a} in equation 1

.25kg\times H_{k}=.6kg\times .5m\\H_{k}=\frac{.3kg\times m}{.25kg} \\H_{k}=1.2m

therefore, Height at which kiwi reach=1.2m

4 0
3 years ago
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