Explanation:
For most temperature scales, the boiling point of water and the freezing point is used to calibrate it.
Three known temperature scales;
- Kelvin scale
- Celcius scale
- Fahrenheit scale
Kelvin scale Celcius scale Fahrenheit scale
Freezing point 273K 0°C 32°F
Melting point 373K 100°C 212°F
Answer:
16.96 W
Explanation:
Power: This can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).
From the question,
P = (F×d)/t....................... Equation 1
Where P = power, F = force, d = distance, t = time.
Given: F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s
Substitute these values into equation 1
P = (75×42)/186
P = 16.94 W
Hence the average power delivered by the child = 16.96 W
Answer:
240cm
Explanation:
Speed = 6cm/s
Time = 40 seconds
Speed= distance/time
6cm/s = distance/40seconds
Distance = 6×40
Distance = 240cm
Hence, in 40 seconds, the ball must have rolled the distance of 240cm
Answer:
The maximum change in flux is 
The average induced emf 
Explanation:
From the question we are told that
The speed of the technician is 
The distance from the scanner is 
The initial magnetic field is 
The final magnetic field is 
The diameter of the loop is 
The area of the loop is mathematically represented as
![A = \pi [\frac{D}{2} ]^2](https://tex.z-dn.net/?f=A%20%20%3D%20%20%5Cpi%20%5B%5Cfrac%7BD%7D%7B2%7D%20%5D%5E2)
At maximum the change in magnetic field is mathematically represented as
=> 
The average induced emf is mathematically represented as
John weighs 200 pounds.
In order to lift himself up to a higher place, he has to exert force of 200 lbs.
The stairs to the balcony are 20-ft high.
In order to lift himself to the balcony, John has to do
(20 ft) x (200 pounds) = 4,000 foot-pounds of work.
If he does it in 6.2 seconds, his RATE of doing work is
(4,000 foot-pounds) / (6.2 seconds) = 645.2 foot-pounds per second.
The rate of doing work is called "power".
(If we were working in the metric system (with SI units),
the force would be in "newtons", the distance would be in "meters",
1 newton-meter of work would be 1 "joule" of work, and
1 joule of work per second would be 1 "watt".
Too bad we're not working with metric units.)
So back to our problem.
John has to do 4,000 foot-pounds of work to lift himself up to the balcony,
and he's able to do it at the rate of 645.2 foot-pounds per second.
Well, 550 foot-pounds per second is called 1 "horsepower".
So as John runs up the steps to the balcony, he's doing the work
at the rate of
(645.2 foot-pounds/second) / (550 ft-lbs/sec per HP)
= 1.173 Horsepower. GO JOHN !
(I'll betcha he needs a shower after he does THAT 3 times.)
_______________________________________________
Oh my gosh ! Look at #26 ! There are the metric units I was talking about.
Do you need #26 ?
I'll give you the answers, but I won't go through the explanation,
because I'm doing all this for only 5 points.
a). 5
b). 750 Joules
c). 800 Joules
d). 93.75%
You're welcome.
And #27 is 0.667 m/s .
