Ask question

Ask question

All categories

3 years ago

12

If she asks you to cut a strip of pie crust long around the outside of the pan, how long does it need to be? (Remember c/d =3.14

.)

1 answer:

Nookie1986 [14]3 years ago

5 0

I remember c/d. That's not a problem. But if you want 'c', you'll have to give me 'd'.

You might be interested in

A rectangular coil with 50 turns of conducting wire and a total resistance of 10.0 Ω initially lies in the yz-plane at time t =

castortr0y [4]

Answer:

a) 43.20V

b) 2.71W/s

c) 40.25s

d) 7.77Nm

Explanation:

(a) The emf of a rotating coil with N turns is given by:

$emf=NBA\omega sin(\omega t)$

N: turns

B: magnitude of the magnetic field

A: area

w: angular velocity

the emf max is given by:

$emf_{max}=NBA\omega=(50)(1.80T)(0.200m*0.100m)(24.0rad/s)\\\\emf_{max}=43.20V$

(b) the maximum rate of change of the magnetic flux is given by:

$\frac{d\Phi_B}{dt}=\frac{d(A\cdot B)}{dt}=\frac{d}{dt}(ABcos\omega t)=AB\omega sin(\omega t)\\\\\frac{d\Phi_B}{dt}_{max}=(\pi(0.200*0.100))(1.80T)(24.0rad/s)=2.71\frac{W}{s}$

(c) $emf(t=0.050s)=(50)(1.80T)(0.200m*0.100m)(24rad/s)sin(24.0rad/s(0.050s))\\\\emf(t=0.050s)=40.26V$

(d) The torque is given by:

$\tau=NABIsin\theta\\\\NAB\omega=emf_{max}\\\\\tau=\frac{emf_{max}}{\omega}\frac{emf_{max}}{R}\\\\\tau=\frac{(43.20V)^2}{(24.0rad/s)(10.0\Omega)}=7.77Nm$

3 0

3 years ago

Which change of state is shown in the model?

Masja [62]

Sublimation is the state shown in the model

7 0

3 years ago

Read 2 more answers

What distance in cm does the light travel in 1 us?

Maksim231197 [3]

108000000. there you go hope it helped

6 0

3 years ago

To calculate the velocity of an object, the of the position vs time graph should be calculated.

Firdavs [7]

The slope of the graph

3 0

3 years ago

Having trouble with a physics class problem. Help?

tekilochka [14]

I just did this lol good luck

8 0

3 years ago