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3 years ago

12

If she asks you to cut a strip of pie crust long around the outside of the pan, how long does it need to be? (Remember c/d =3.14

.)

1 answer:

Nookie1986 [14]3 years ago

5 0

I remember c/d. That's not a problem. But if you want 'c', you'll have to give me 'd'.

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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.6 multiply 1010 m (inside t

Doss [256]

We will apply the concepts related to energy conservation to develop this problem. In this way we will consider the distances and the given speed to calculate the final speed on the path from the sun. Assuming that the values exposed when saying 'multiply' is scientific notation we have the following,

$d_1 = 4.6*10^{10}m$

$v_i = 9.3*10^4m/s \rightarrow \text{Initial velocity comet}$

$d_2 = 6*10^{12}m$

The difference of the initial and final energy will be equivalent to the work done in the system, therefore

$E_f = E_i +W$

$K_f +U_f = K_i +U_i + 0$

$\frac{1}{2} mv_f^2+\frac{-GMm}{d_2} = \frac{1}{2} mv_i^2+\frac{-GMm}{d_1}$

Here,

m = Mass

$v_f$ = Final velocity

G = Gravitational Universal Constant

M = Mass of the Sun

m = Mass of the comet

$v_i$ = Initial Velocity

Rearranging to find the final velocity,

$v_f = \sqrt{v_i^2+2GM(\frac{1}{d_2}-\frac{1}{d_1})}$

Replacing with our values we have finally,

$v_f = \sqrt{(9.3*10^4)+2(6.7*10^{-11})(1.98*10^{30})(\frac{1}{6*10^{12}}-\frac{1}{4.6*10^{10}})}$

$v_f = 75653.9m/s$

Therefore the speed is 75653m/s

8 0

4 years ago

A light meterstick is loaded with masses of5.0 kg and 3.0 kg

fredd [130]

Answer: $I=3.024\ kg-m^2$

Explanation:

Given

mass of first $m_1=5 kg$

mass of second $m_2=3 kg$

Distance of $m_1$ from origin $r_1=36 cm$

Distance of $m_2$ from origin $r_2=89 cm$

Moment of inertia is given by multiplication of mass and square of distance

$I=\sum mr^2$

$I=m_1r_1^2+m_2r_2^2$

$I=5\times 0.36^2+3\times 0.89^2$

$I=0.648+2.376$

$I=3.024\ kg-m^2$

3 0

3 years ago

Read 2 more answers

Two coherent sources of radio waves, A and B, are 5.00 metersapart. Each source emits waves with wavelength 6.00 meters.Consider

alexgriva [62]

Answer

given,

distance between A and B is equal to 5 m

let x be the distance of loud speaker from the source A

For constructive interference, path difference = mλ

x - (5 - x ) = 0 , for m = 0

2 x - 5 = 0

2 x = 5

x = 2.5 cm

For destructive interference

$|x - (5 - x )| = (2 m + 1)\dfrac{\lambda}{2}$

m = 0

$|2x - 5| = \dfrac{\lambda}{2}$

$|2x - 5| = \dfrac{6}{2}$

$\pm(2x - 5) = 3$

x = 4 , 1 cm

3 0

3 years ago

Which statement is true about the law of conservation of energy for an object released from a certain height above the ground

gregori [183]

The question is really specific enough, but I will take a guess. If nothing else changes (like the mass or the gravitational constant) then the Potential Energy will increase with an increase in height. Ep will decrease with a decrease in height.

If you are talking about Ke, then the height does not matter unless the object is moving up. Then it slows down. When that happens the Ke decreases because the formula for Ke = 1/2 m v^2. If v becomes less then Ke becomes less.

I suppose you could say if the object is going down and the distance is decreasing then the speed will increase. It's an inverse relationship.

I think you are best talking about Pe.

6 0

4 years ago

A force of 10N makes an angle of 30 degree with y-axis. The magnitude of X component will be?

andreev551 [17]

The magnitude of x component is 5N

4 0

3 years ago