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azamat
3 years ago
7

How can i find the acceleration?(rope and grinder have no weight) *** sorry for my english

Physics
1 answer:
Finger [1]3 years ago
7 0
The main formula to be used here is

                       Force = (mass) x (acceleration).

We'll get to work in just a second.  But first, I must confess to you that I see
two things happening here, and I only know how to handle one of them.  So
my answer will be incomplete, but I believe it will be more reliable than the
first answer that was previously offered here.

On the <u>right</u> side ... where the 2 kg and the 3 kg are hanging over the same
pulley, those weights are not balanced, so the 3 kg will pull the 2kg down, with
some acceleration.  I don't know what to do with that, because . . .

At the <em>same time</em>, both of those will be pulled <u>up</u> by the 10 kg on the other side
of the upper pulley.

I think I can handle the 10 kg, and work out the acceleration that IT has.

Let's look at only the forces on the 10 kg:

-- The force of gravity is pulling it down, with the whatever the weight of 10 kg is.

-- At the same time, the rope is pulling it UP, with whatever the weight of 5 kg is ...
that's the weight of the two smaller blocks on the other end of the rope. 

So, the net force on the 10 kg is the weight of (10 - 5) = 5 kg, downward.

The weight of 5 kg is (mass) x (gravity) = (5 x 9.8) = 49 newtons.

The acceleration of 10 kg, with 49 newtons of force on it, is

     Acceleration = (force) / (mass) = 49/10 = <em>4.9 meters per second²</em>
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Which image shows the difference between the speed of molecules in hot and cold water? Explain your answer choice.
Leto [7]
There is no image btw
7 0
2 years ago
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A gardener pushes a wheelbarrow around the edges of a lawn. When she has finished, she is 5 m from her starting point. She has t
zvonat [6]

Answer:

Work done by the gardner is 500 J

Explanation:

As we know that the gardner apply force perpendicular upward by magnitude 300 N and along the floor horizontal force is 100 N

so we have

F = 100 \hat i + 300 \hat j

now the displacement of the gardner along the floor is

d = 5\hat i

now work done is given as

W = F. d

so we have

W = (100 \hat i + 300 \hat j). (5\hat i)

W = 500 J

3 0
2 years ago
A car is travelling with a velocity 90 km/hr and other with 72 km/hr in opposite direction, find the relative velocity between t
satela [25.4K]

Answer:

590km pls brainlist

Explanation:

jjjuue

7 0
2 years ago
An ac generator has a maximum emf output of 150 V. What is the rms current in the circuit when the generator is connected to a 3
natima [27]

This is an insidious question.  Quite frankly, I would not have
expected to see it here on Brainly.  But I'm ready to play the
cards that you have dealt me.

None of the choices offered is a correct solution.

If the output of the AC generator is nice and sinusoidal, and
its maximum (peak) emf is 150 volts, then its RMS emf is

                             (1/2) (150) (√2)  =  106.07 volts.

The resistor's dissipation is   

                             Power = (current) x (voltage) .

If the resistor is dissipating its full rated 35W, then

                       35W  =  (current) x (106.07 V)

Divide each side by 106.07 V:   

           RMS Current =  (35W) / (106.07 V)  =  0.33 Ampere .
_________________________________________

Looking over the choices offered . . . 

The largest choice ... 3.1 A ... is the current in a resistor
that is dissipating 35W if the voltage is

                           (35W / 3.1A)  =  11.29 volts .

The smallest choice ... 1.2 A ... is the current in a resistor
that is dissipating 35W if the voltage is

                           (35W / 1.2A)  =  29.17 volts .

Whatever you meant the so-called "150 V" of the generator
to represent ... whether the RMS sinusoidal, peak sinusoidal,
peak square-wave, RMS square-wave, DC, average, etc. ...
none of the choices for current, in combination with any of these
generators, would dissipate 35W.

3 0
3 years ago
You need to design a 60.0-Hz ac generator that has a maximum emf of 5500 V. The generator is to contain a 150-turn coil that has
olchik [2.2K]

Answer:

So magnetic field will be equal to 0.1144 T  

Explanation:

We have given frequency f = 60 Hz

Maximum emf e = 5500 volt

Number of turns N = 150

Area A=0.85m^2

Emf generated in ac generator is given e=NBA\omega sin(\omega t)

For maximum emf sin(\omega t)=1

So maximum emf will be equal to e=NBA\omega

B=\frac{e}{NA\omega }=\frac{5500}{150\times 2\times 3.14\times 60\times 0.85}=0.1144T

So magnetic field will be equal to 0.1144 T

3 0
2 years ago
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