This question involves the concepts of general gas equation and pressure.
The force exerted by the gas on one of the walls of the container is "74.08 KN".
First, we will use the general gas equation to find out the pressure of the gas:

where,
P = Pressure of the gas = ?
V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³
n = no. of moles = 3 (since molecules equal to avogadro's number make up 1 mole)
R = general gas constant = 8.314 J/mol.K
T = Absolute Temperature = 24°C + 273 = 297 K
Therefore,

P = 7407.78 KPa
Now, the force on one wall can be given as follows:

where,
A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²
Therefore,

<u>F = 74.08 KN</u>
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Learn more about the general gas equation here:
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Cartography (the making of maps and charts) is a science because it is a body of knowledge which can be used, built on, and can produce testable hypotheses.
The cartography of India begins with early charts for navigation and constructional plans for buildings. Indian traditions influenced Tibetan and Islamic traditions, and in turn, were influenced by the British cartographers who solidified modern concepts into India's map making
The circular shape allows the tire to roll easily with the least amount of bumps or jolts
Answer:
3m/s
Explanation:
Given parameters:
Initial speed = 2m/s
Acceleration = 0.5m/s²
Time = 2s
Unknown:
Final speed = ?
Solution:
To solve this problem, we apply the right motion equation;
V = U + at
V is the final speed
U is the initial speed
a is the acceleration
t is the time
V = 2 + (2 x 0.5)
V = 2 + 1
V = 3m/s