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Archy [21]
3 years ago
5

At what pressure does the mean free path of argon at 20 degrees celsius become comparable to the diameter of a 100 cm3​vessel th

at contains it? Please note sigma= 0.36 nm2​. Sigma= collision cross section of argon.
Chemistry
1 answer:
inn [45]3 years ago
5 0

Answer:

The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa

Explanation:

<u>Step 1</u>: Calculate the volume of a spherical container V

V = (4π*r³)/3

r = (3V/4π)^1/3

2r = d = 2*(3V/4π)^1/3

with r= radius

with d= diameter

The diameter is:

d= 2*(3V/4π)^1/3

d= 2*(3*100cm³/4π)^1/3

d= 5.76 cm

<u>Step2 </u>: Define the free path lambda  λ of argon

with  λ =k*T/ σp

with p = kT/σλ

with T= temperature = 20°C = 293.15 Kelvin

with k = Boltzmann's constant = 1.381 * 10^-23 J/K

with p = the atmospheric pressure

with σ = 0.36 nm²

p = kT/σλ

p = (1.38 * 10^-23 J*K^-1 * 1Pa *m³/1J)*(293,15K) /(0.36 nm²*(10^-9/ 1nm)² *(5.76cm* 10^-2m/1cm)

p = 0.195 Pa

The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa

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LekaFEV [45]

Answer:

0.776 ×10²³ atoms of oxygen

Explanation:

Given data:

Mass of Al₂CO₃ = 10.0 g

Number of atoms of oxygen = ?

Solution:

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This is much more simple than it sounds... 

s has 1 orbital; p = 3 orbitals; d= 5 orbitals; f= 7 orbitals. (you just need to memorize this) 
A maximum of 2 electrons can occupy each orbital. 

<span>The number of orbitals that each atom has is based on the number of electrons it has and by consequence it's position on the periodic table. </span>

The orbitals occur in sequence. Whereby electrons fill first from the lowest energy level (1s) outwards to the highest. 
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The sequence through n=4 is: 

<span>1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f 
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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