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mylen [45]
3 years ago
8

The chart below includes images of different structures found in animals or plants for each structure describe The smaller livin

g unit that makes up the structure also describe the next largest living unit by your answer directly in the chart next to each image watch out some structures may not have a smaller or larger living unit the first one is done for you

Physics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

sorry can't understand the question

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Explain why gases are more compressible than solid
Oduvanchick [21]

Answer:

If we put pressure on a solid or a liquid, there is essentially no change in volume. ... The kinetic-molecular theory explains why gases are more compressible than either liquids or solids. Gases are compressible because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.

Explanation:

7 0
3 years ago
A barrel 1 m tall and 60 cm in diameter is filled to the top with water. What is the pressure it exerts on the floor beneath it?
allsm [11]

Answer:

The pressure on the ground is about 9779.5 Pascal.

The pressure can be reduced by distributing the weight over a larger area using, for example, a thin plate with an area larger than the circular area of the barrel's bottom side.  See more details further below.

Explanation:

Start with the formula for pressure

(pressure P) = (Force F) / (Area A)

In order to determine the pressure the barrel exerts on the floor area, we need the calculate the its weight first

F_g = m \cdot g

where m is the mass of the barrel and g the gravitational acceleration. We can estimate this mass using the volume of a cylinder with radius 30 cm and height 1m, the density of the water, and the assumption that the container mass is negligible:

V = h\pi r^2=1m \cdot \pi\cdot 0.3^2 m^2\approx 0.283m^3

The density of water is 997 kg/m^3, so the mass of the barrel is:

m = V\cdot \rho = 0.283 m^3 \cdot 997 \frac{kg}{m^3}= 282.151kg

and so the weight is

F_g = 282.151kg\cdot 9.8\frac{m}{s^2}=2765.08N

and so the pressure is

P = \frac{F}{A} = \frac{F}{\pi r^2}= \frac{2765.08N}{\pi \cdot 0.3^2 m^2}\approx 9779.5 Pa

This answers the first part of the question.

The second part of the question asks for ways to reduce the above pressure without changing the amount of water. Since the pressure is directly proportional to the weight (determined by the water) and indirectly proportional to the area, changing the area offers itself here. Specifically, we could insert a thin plate (of negligible additional weight) to spread the weight of the barrel over a larger area. Alternatively, the barrel could be reshaped (if this is allowed) into one with a larger diameter (and smaller height), which would achieve a reduction of the pressure.  

7 0
3 years ago
John and Daniel are playing tug-of-war together. John is exerting 10 N of force. Daniel is exerting 12 N of force. What is their
vovangra [49]

YEP ITS D 2 N in Daniel's direction

8 0
3 years ago
Read 2 more answers
A 2550 pound roller coaster starts from rest and is launched such that it crests a 119 ft high hill with a speed of 57 mph. The
Feliz [49]

To solve this problem we will apply the concepts related to energy conservation. For this purpose we will have that all the changes occurred in the energy change will be equivalent to the change in the potential and kinematic energies of the body. At the same time we will consider that the change in the final energy of the system will be reflected in the work of the system, therefore,

\Delta E = KE+PE

E_i - Fd = \frac{1}{2}mv^2+Wh

Here,

F = Force

m = mass

v = Velocity

h = Height

d = Distance

W = mg \rightarrow \text{Weight/Force Weight}

E_i =\frac{1}{2}mv^2+Wh+Fd

E_i = \frac{1}{2} (\frac{W}{g})v^2 +Wh+fd

Replacing we have,

E_i = \frac{1}{2} (\frac{2550pounds}{32.2ft/s^2})(57mi/h(\frac{1.467ft/s}{1mi/h}))+(2550pounds)(119ft)+(100pounds)(583ft)

E_i =365061ft\cdot lb

Therefore the launch energy is 365061ft-lb

3 0
3 years ago
When Patey Pontoons issued 10% bonds on January 1, 2021, with a face amount of $720,000, the market yield for bonds of similar r
wlad13 [49]

Answer:

Explanation:

Interest is paid semiannually on June 30 and December 31. (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided.) Required: 1. Determine the price of the bonds on January 1, 2021. 2. Prepare the journal entry to record their issuance by Patey on January 1, 2021. 3. Prepare an amortization schedule that determines interest at the effective rate for each period. 4. Prepare the journal entry to record interest on June 30, 2021. 5. What is the amount related to the bonds that Patey will report in its balance sheet on December 31, 2021? 6. What is the amount related to the bonds that Patey will report in its income statement for the year ended December 31, 2021? (Ignore income taxes.) 7. Prepare the appropriate journal entries at maturity on December 31, 2024. Complete this question by entering your answers in the tabs below. Req 1 Reg 2 Reg 2 Req 3 Req3 Req 4 Req 4 Req 5 and 6 Req 7 Reg 7 Determine the price of the bonds at January 1, 2021. (Round final answers to the nearest whole dollar.) Table values are based on: n = Cash Flow Amount Present Value Interest Principal Price of bonds Req 1 Reg 2 Req 3 Req 4 Req 5 and 6 Req 7 Prepare the journal entry to record their issuance by Patey on January 1, 2021. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Round intermediate calculations and final answers to the nearest whole dollar.) View transaction list 1 Record the issuance of the bonds on January 1, 2021. Req 1 Req 2 Req3 Req 4 Req 5 and 6 Req 7 Prepare an amortization schedule that determines interest at the effective rate for each period. (Round intermediate calculations and final answers to the nearest whole dollar.) ...................... Semiannual Bond Interest Discount Interest Cash Interest Carrying Value Period-End Expense Amortization 01/01/2021 06/30/2021 12/31/2021 06/30/2022 12/31/2022 06/30/2023 12/31/2023 06/30/2024 12/31/2024 Total Req 1 Req 2 Req 3 Reg 4 Req 5 and 6 Req 7 Prepare the journal entry to record interest on June 30, 2021. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Round intermediate calculations and final answers to the nearest whole dollar.) View transaction list 1 Record the interest expense on June 30, 2021. Complete this question by entering your answers in the tabs below. Reg 1 Req 2 Req 3 Req 4 Req 5 and 6 Req 7 What is the amount(s) related to the bonds that Patey will report in its balance sheet on December 31, 2021, and income statement for the year ended December 31, 2021? (Ignore income taxes.) (Round intermediate calculations and final answers to the nearest whole dollar.) 5. December 31, 2021 book value 6. Interest expense for 2021 Req 1 Req 2 Req3 Req 4 Req 5 and 6 Req 7 Prepare the appropriate journal entries at maturity on December 31, 2024. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Round intermediate calculations and final answers to the nearest whole dollar.) View transaction list X 1 Record the interest expense on December 31, 2024. 2 Record the retirement of the bond at maturity on December 31, 2024.

3 0
3 years ago
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