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Kazeer [188]
2 years ago
14

What is the magnitude of the electric field at the dot in the figure?

Physics
1 answer:
Zielflug [23.3K]2 years ago
8 0

The magnitude of the electric field at the dot is :  10⁴ v/m

Given that there are three equipotential lines with equal spacing,we will apply the the relationship between P.D and electric field

<h3>Determine the magnitude of the electric field at the dot </h3>

change in voltage  = E .d

100 - 0 = E * ( 1 * 10⁻² m ) ----- ( 1 )

From equation ( 1 )

The magnitude of E = 100 v / ( 1 * 10⁻² m )

                                 = 10⁴ v/m

Hence we can conclude that The magnitude of the electric field at the dot is :  10⁴ v/m

Learn more about electric field : brainly.com/question/14372859

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Answer:

First, the different indices of refraction must be taken into account (in different media): for example, the refractive index of light in a vacuum is 1 (since vacuum = c).  The value of the refractive index of the medium is a measure of its "optical density":  Light spreads at maximum speed in a vacuum but slower in others  transparent media; therefore in all of them n> 1. Examples of typical values ​​of  are those of air (1,0003), water (1.33), glass (1.46 - 1.66) or diamond (2.42).

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