All categories

2 years ago

What is the magnitude of the electric field at the dot in the figure?

Physics

1 answer:

Zielflug [23.3K]2 years ago

8 0

The magnitude of the electric field at the dot is : 10⁴ v/m

Given that there are three equipotential lines with equal spacing,we will apply the the relationship between P.D and electric field

<h3>Determine the magnitude of the electric field at the dot </h3>

change in voltage = E .d

100 - 0 = E * ( 1 * 10⁻² m ) ----- ( 1 )

From equation ( 1 )

The magnitude of E = 100 v / ( 1 * 10⁻² m )

= 10⁴ v/m

Hence we can conclude that The magnitude of the electric field at the dot is : 10⁴ v/m

Learn more about electric field : brainly.com/question/14372859

You might be interested in

Which of these phase changes requires energy?

frutty [35]

Answer:

Explanation:

You have to give energy away for B. You have to think about that carefully. The CO2 starts out with a great deal of energy (mostly KE) and has to slow down to go from gas to a solid. Not B

In general C is the same way. Water has more energy than ice. Not C

Same principle in D. Not D.

So it's A

7 0

2 years ago

A vicious dog is pulling his owner with 150N of force . If the owner is dragged 40 meters , how much work did the dog do ?

Angelina_Jolie [31]

Afor:6000Nm

Explanation: work=force×distance

Work=150×40

Work=6000Nm

4 0

3 years ago

Not including thinking distance, lawful brakes must stop a car at 20 miles per hour within how many feet?

Svetradugi [14.3K]

Answer:

B. 25 feet

Explanation:

In most cities in US, passenger car brakes must stop a car moving at 20 miles per hour at 25 feet.

Therefore, the correct option is "B" 25 feet

5 0

3 years ago

Read 2 more answers

A cyclist travels at 15 m/s during a sprint finish. What is this speed in km/h

g100num [7]

Answer:

54 km/hr

Explanation:

m/s to km/hr => 18/5

15 m/s to km/hr => 15 x 18/5 =>3 x 18 => 54km/hr

8 0

3 years ago

A laser beam is incident at an angle of 30.0° from the vertical onto a solution of corn syrup in water. The beam is refracted to

dimaraw [331]

Answer with Explanation:

We are given that

Angle of incidence, $i=30^{\circ}$

Angle of refraction, $r=19.24^{\circ}$

a.Refractive index of air, $n_1=1$

We know that

$n_2sinr=n_1sini$

$n_2=\frac{n_1sin i}{sin r}=\frac{sin30}{sin19.24}=1.517$

b.Wavelength of red light in vacuum, $\lambda=632.8nm=632.8\times 10^{-9} m$

$1nm=10^{-9} m$

Wavelength in the solution, $\lambda'=\frac{\lambda}{n_2}$

$\lambda'=\frac{632.8}{1.517}=417nm$

c.Frequency does not change .It remains same in vacuum and solution.

Frequency, $\nu=\frac{c}{\lamda}=\frac{3\times 10^8}{632.8\times 10^{-9}}$

Where $c=3\times 10^8 m/s$

Frequency, $\nu=4.74\times 10^{14}Hz$

d.Speed in the solution, $v=\frac{c}{n_2}$

$v=\frac{3\times 10^8}{1.517}=1.98\times 10^8m/s$

5 0

3 years ago