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3 years ago

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What is the difference between a stepped and a non-stepped ECT circuit?

1 answer:

galina1969 [7]3 years ago

5 0

Answer:

A stepped circuit is designed in the engine coolant temperature (ECT) sensor within a powertrain control module (PCM) to increase the sensor's accuracy. A simple non-stepped ECT sensor circuit has a specific resistance which increases or decreases according to the changes in engine coolant temperature.

Explanation:

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ITS FOR DRIVERS ED!!

Nastasia [14]

I got “driving is a privilege”

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3 years ago

Read 2 more answers

A 3-m wide rectangular channel has a flow velocity of 1.8 m/s when the depth of flow is 1.2 m. what will be the flow velocity wh

valina [46]

Answer:

The flow velocity reduces to 0.72 m/s

Explanation:

According to the equation of continuity discharge in the channel should remain same

Thus we have

$A_{1}V_{1}=A_{2}V_{2}$

For a rectangular channel we have $Area=Depth\times Width$

Applying values in the continuity equation and since the width of the channel remains constant 3.0 m we have

$3\times 1.8\times 1.2=3\times 3\times V_{2}\\\\\therefore V_{2}=\frac{6.48}{9}=0.72m/s$

6 0

3 years ago

Water of dynamic viscosity 1.12E-3 N*s/m2 flows in a pipe of 30 mm diameter. Calculate the largest flowrate for which laminar fl

Naya [18.7K]

Answer:

For water

Flow rate= 0.79128*10^-3 Ns

For Air

Flow rate =1.2717*10^-3 Ns

Explanation:

For the flow rate of water in pipe.

Area of the pipe= πd²/4

Diameter = 30/1000

Diameter= 0.03 m

Area= 3.14*(0.03)²/4

Area= 7.065*10^-4

Flow rate = 7.065*10^-4*1.12E-3

Flow rate= 0.79128*10^-3 Ns

For the flow rate of air in pipe.

Flow rate = 7.065*10^-4*1.8E-5

Flow rate =1.2717*10^-3 Ns

7 0

3 years ago

The type of current that flows from the electrode across the arc to the work is called what?

Scrat [10]

Answer:

Direct current.

Explanation:

5 0

3 years ago

An astronomer of 65 kg of mass hikes from the beach to the observatory atop the mountain in Mauna Kea, Hawaii (altitude of 4205

lara [203]

Answer:

$0.845\ \text{N}$

Explanation:

g = Acceleration due to gravity at sea level = $9.81\ \text{m/s}^2$

R = Radius of Earth = 6371000 m

h = Altitude of observatory = 4205 m

Change in acceleration due to gravity due to change in altitude is given by

$g_h=g(1+\dfrac{h}{R})^{-2}\\\Rightarrow g_h=9.81\times(1+\dfrac{4205}{6371000})^{-2}\\\Rightarrow g_h=9.797\ \text{m/s}^2$

Weight at sea level

$W=mg\\\Rightarrow W=65\times 9.81\\\Rightarrow W=637.65\ \text{N}$

Weight at the given height

$W_h=mg_h\\\Rightarrow W_h=65\times 9.797\\\Rightarrow W_h=636.805\ \text{N}$

Change in weight $W_h-W=636.805-637.65=-0.845\ \text{N}$

Her weight reduces by $0.845\ \text{N}$ .

8 0

3 years ago