Answer:
Explanation:
Given
velocity at A is ![v=4\ ft/s](https://tex.z-dn.net/?f=v%3D4%5C%20ft%2Fs)
For ![r=500\ ft](https://tex.z-dn.net/?f=r%3D500%5C%20ft)
velocity is increasing at ![\dot{v}=0.004t\ ft/s^2](https://tex.z-dn.net/?f=%5Cdot%7Bv%7D%3D0.004t%5C%20ft%2Fs%5E2)
Tangential acceleration is given by
![a_t=\frac{\mathrm{d} v}{\mathrm{d} t}](https://tex.z-dn.net/?f=a_t%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20v%7D%7B%5Cmathrm%7Bd%7D%20t%7D)
![a_t=0.004t=\frac{\mathrm{d} v}{\mathrm{d} t}](https://tex.z-dn.net/?f=a_t%3D0.004t%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20v%7D%7B%5Cmathrm%7Bd%7D%20t%7D)
![\int 0.004tdt=\int dv](https://tex.z-dn.net/?f=%5Cint%200.004tdt%3D%5Cint%20dv)
![\int dv=\int 0.004tdt](https://tex.z-dn.net/?f=%5Cint%20dv%3D%5Cint%200.004tdt)
![v=0.002t^2+c](https://tex.z-dn.net/?f=v%3D0.002t%5E2%2Bc)
at ![t=0\ v=4\ ft/s](https://tex.z-dn.net/?f=t%3D0%5C%20v%3D4%5C%20ft%2Fs)
![4=0.002\cdot 0+c](https://tex.z-dn.net/?f=4%3D0.002%5Ccdot%200%2Bc)
![c=4\ ft/s](https://tex.z-dn.net/?f=c%3D4%5C%20ft%2Fs)
thus ![v=0.002t^2+4](https://tex.z-dn.net/?f=v%3D0.002t%5E2%2B4)
Velocity in terms of Displacement is given by
![v=\frac{\mathrm{d} s}{\mathrm{d} t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20s%7D%7B%5Cmathrm%7Bd%7D%20t%7D)
![\Rightarrow \int ds=\int \left ( 0.002t^2+4\right )dt](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cint%20ds%3D%5Cint%20%5Cleft%20%28%200.002t%5E2%2B4%5Cright%20%29dt)
![\Rightarrow s=\frac{0.002t^3}{3}+4t](https://tex.z-dn.net/?f=%5CRightarrow%20s%3D%5Cfrac%7B0.002t%5E3%7D%7B3%7D%2B4t)
When car has traveled
th of distance i.e.
![s=\frac{3}{4}\times (2\pi r)=\frac{3\pi r}{2}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B3%7D%7B4%7D%5Ctimes%20%282%5Cpi%20r%29%3D%5Cfrac%7B3%5Cpi%20r%7D%7B2%7D)
![s=750\pi](https://tex.z-dn.net/?f=s%3D750%5Cpi%20)
![750\pi =\frac{0.002t^3}{3}+4t](https://tex.z-dn.net/?f=750%5Cpi%20%3D%5Cfrac%7B0.002t%5E3%7D%7B3%7D%2B4t)
![\Rightarrow \frac{0.002t^3}{3}+4t-2356.5=0](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac%7B0.002t%5E3%7D%7B3%7D%2B4t-2356.5%3D0)
on solving we get ![t=139.23\ s](https://tex.z-dn.net/?f=t%3D139.23%5C%20s)
Thus velocity at ![t=139.23\ s](https://tex.z-dn.net/?f=t%3D139.23%5C%20s)
![v=42.76\ s](https://tex.z-dn.net/?f=v%3D42.76%5C%20s)
(b)Acceleration when car has traveled three-fourth the way of track
normal acceleration ![a_n=\frac{v^2}{r}=\frac{(42.76)^2}{500}](https://tex.z-dn.net/?f=a_n%3D%5Cfrac%7Bv%5E2%7D%7Br%7D%3D%5Cfrac%7B%2842.76%29%5E2%7D%7B500%7D)
![a_n=3.658\ m/s^2](https://tex.z-dn.net/?f=a_n%3D3.658%5C%20m%2Fs%5E2)
Tangential acceleration ![a_t at t=139.23\ s](https://tex.z-dn.net/?f=a_t%20at%20t%3D139.23%5C%20s)
![a_t=0.556\ m/s^2](https://tex.z-dn.net/?f=a_t%3D0.556%5C%20m%2Fs%5E2)
Net acceleration ![a_t=\sqrt{(a_n)^2+(a_t)^2}](https://tex.z-dn.net/?f=a_t%3D%5Csqrt%7B%28a_n%29%5E2%2B%28a_t%29%5E2%7D)
![a_n=\sqrt{(3.658)^2+(0.556)^2}](https://tex.z-dn.net/?f=a_n%3D%5Csqrt%7B%283.658%29%5E2%2B%280.556%29%5E2%7D)
Flip-flops are normally used for all of the following applications, except logic gates.
<h3>What are Flip flops?</h3>
Flip flops are known to be tools that are used for counting. They come in different ranges.
Note that Flip flops are one that can be seen on counters, storage registers, and others and as such, Flip-flops are normally used for all of the following applications, except logic gates.
Learn more about Flip flops from
brainly.com/question/4237777
#SPJ1
Answer =
dial bore gauge
a “dial bore gauge” measures the inside of round holes, such as the bearing journals . can mesure up to 2” and 6” diameter holes .
when ( “ ) is next to a number it means inches fwi - but hope this helped have a good day :)
Answer:
point_dist = math.sqrt((math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2))
Explanation:
The distance formula is the difference of the x coordinates squared, plus the difference of the y coordinates squared, all square rooted. For the general case, it appears you simply need to change how you have written the code.
point_dist = math.sqrt((math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2))
Note, by moving the 2 inside of the pow function, you have provided the second argument that it is requesting.
You were close with your initial attempt, you just had a parenthesis after x1 and y1 when you should not have.
Cheers.
Answer:
L= 50000 lb
D = 5000 lb
Explanation:
To maintain a level flight the lift must equal the weight in magnitude.
We know the weight is of 50000 lb, so the lift must be the same.
L = W = 50000 lb
The L/D ratio is 10 so
10 = L/D
D = L/10
D = 50000/10 = 5000 lb
To maintain steady speed the thrust must equal the drag, so
T = D = 5000 lb