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3 years ago

What would be the slope for this problem?

Mathematics

2 answers:

kondaur [170]3 years ago

8 0

The slope of that line is 0

elixir [45]3 years ago

5 0

Y = 0x + 3

Please mark brainiest :)

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a boat leaves port at 13:52 and arrives at its destination 3 and a half hours later. at what time does the boat arrive

Temka [501]

16:52

Hope this helps! :)

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3 years ago

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What are the dimensions of a storage tank

motikmotik

Answer:

Step-by-step explanation:

550 48 6-0 3/16 3/16 800

1000 48 10-10 3/16 3/16 1300

1100 48 11-11 3/16 3/16 1400

1500 48 15-8 3/16 3/16 1650

65 9-0 3/16 3/16 1500

2000 65 11-10 3/16 3/16 2050

2500 65 14-10 3/16 3/16 2275

3000 65 17-8 3/16 3/16 2940

4000 65 23-8 3/16 3/16 3600

5000 72 23-8 1/4 1/4 5800

84 17-8 1/4 1/4 5400

7500 84 26-6 1/4 1/4 7150

96 19-8 1/4 1/4 6400

10000 96 26-6 1/4 5/16 8540

120 17-0 1/4 5/16 8100

12000 96 31-6 1/4 5/16 10500

120 20-8 1/4 5/16 9500

15000 108 31-6 5/16 5/16 13300

120 25-6 5/16 5/16 12150

20000 120 34-6 5/16 5/16 15500

25000 120 42-6 3/8 3/8 22300

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3 years ago

Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr

NNADVOKAT [17]

Answer:

C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Distance between B(0, 5) and C(4, 2):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(0, 5) = (x_1, y_1)$

$C(4, 2) = (x_2, y_2)$

$BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}$

$BC = \sqrt{(4)^2 + (-3)^2}$

$BC = \sqrt{16 + 9} = \sqrt{25}$

$BC = 5 units$

Distance between C(4, 2) and D(1, -2)

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(4, 2) = (x_1, y_1)$

$D(1, -2) = (x_2, y_2)$

$CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}$

$CD = \sqrt{(-3)^2 + (-4)^2}$

$CD = \sqrt{9 + 16} = \sqrt{25}$

$CD = 5 units$

Distance between E(-2, -2) and F(-5, 2):

$EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$E(-2, -2) = (x_1, y_1)$

$F(-5, 2) = (x_2, y_2)$

$EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}$

$EF = \sqrt{(-3)^2 + (4)^2}$

$EF = \sqrt{9 + 16} = \sqrt{25}$

$EF = 5 units$

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0

3 years ago

The equation of a parabola in vertex form is y = 2(x - 3)2 + 5. What is the standard form

Alexxx [7]

hello :

y = 2(x + 3)² - 5

y = 2(x²+6x+9) -5

y = 2x² +12x +13...(answer : A) y=2x^2+12x+13 )

Option (a) is correct.

The standard form the equation is

Step-by-step explanation:

Given : the vertex form of the equation of a parabola is

We have to write the given equation in standard form and choose the correct from the given options.

Consider the given equation of parabola

The standard form of equation of parabola is

We can obtain the standard form by expanding the square term in the given equation.

Using algebraic identity , we have,

Solving brackets, we get,

Simplify, we get,

Thus, The standard form the equation is

7 0

2 years ago

I need help please now now now

xeze [42]

Use m a t h w a y . C o m
It can help you will all of your math homework

6 0

3 years ago

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