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3 years ago

What would be the slope for this problem?

Mathematics

2 answers:

kondaur [170]3 years ago

8 0

The slope of that line is 0

elixir [45]3 years ago

5 0

Y = 0x + 3

Please mark brainiest :)

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What what is is tan B?

timofeeve [1]

Answer:

Tan B= 16/30

Step-by-step explanation:

Remember SOH CAH TOA. Tan is involved with this problem so we would use the TOA. TOA stands for: T-Tan, O- Opposite, and A- Adjacent.

First you want to find what is the opposite side of angle B (in meaning the side if you go straight out from the angle) which would be 16. You then need to find the adjacent side which is the side in between the given angle and 90 degree angle so that would be 30. TOA states that Opposite is over Adjacent so it would be 16/30.

4 0

3 years ago

Read 2 more answers

Solve the system 2x+2y+z=-2 -x-2y+2z=-5 2x+4y+z=0

drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

Step-by-step explanation:

The given is,

$2x+2y+z=- 2$ .......................................(1)

$-x-2y+2z=-5$ ......................................(2)

$2x+4y+z=0$ .........................................(3)

Step:1

Equation (2) is multiplied by -1 ( Eqn(2) × -1 )

$x+2y-2z=5$ .............................(4)

Subtract the equation (1) and (4)

$2x+2y+z=- 2$

$x+2y-2z=5$

( - )

$(2x-x)+(2y-2y)+(z+2z)=(-2-5)$

$x+3z=-7$ ......................(5)

Step:2

Equation (2) is multiplied by -2 ( Eqn(2) × -2)

$2x+4y-4z=10$ ........................(6)

Subtract equation (6) and (3),

$2x+4y-4z=10$

$2x+4y+z=0$

( - )

$(2x-2x)+(4y-4y)+(-4z-z)= (10-0)$

$-5z=10$

$z = - \frac{10}{5}$

z = -2

From the equation (5),

$x+3z=-7$

$x+(3)(-2)=-7$

$x = -7+6$

x = -1

From equation (1),

$2x+2y+z=- 2$

Substitute x and z values,

$(2)(-1)+2y+(-2)=-2$

$2y - 4=2$

$2y=4-2$

$2y=2$

$y=\frac{2}{2}$

y = 1

Step:3

Check for solution,

$-x-2y+2z=-5$

Substitute x,y and z values,

$-(-1)-(2)(1)+(2)(-2)=-5$

$1-2-4=-5$

-5 = -5

Result:

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

8 0

4 years ago

Y=x+3 y=2x+5 PLZ HELP! I NEED IT SOOOOOOOO BAD!!!

natita [175]

Because both equations are equal to y, you can set the equations equal to each other.

2x+5= x+3
-x -x
x+5=3
-5 -5
x= -2

Then, you can substitute -2 to any equation to find x.

y= (-2)+3 y= 2(-2)+5
y= 1 y= -4+5
y=1

:
x=-2
y=1

4 0

4 years ago

Solve for x in the equation x^2-14+31=63

Bingel [31]

To solve for a variable, you need to get it (x) by itself.

x² - 14 + 31 = 63 Add 31 to -14
x² + 17 = 63 Subtract 17 from both sides of the equation
x² = 46 Square root both sides
x = $\pm \sqrt{46}$

Check your work by plugging in $\sqrt{46}$ for x and then $- \sqrt{46}$ .

$\sqrt{46}$ ² - 14 + 31 = 63 Square $\sqrt{46}$
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63

$- \sqrt{46}$ ² - 14 + 31 = 63 Square $- \sqrt{46}$
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63

So, x is $\sqrt{46}$ and $- \sqrt{46}$ .

3 0

3 years ago

In the following diagram, points C, A, and B are collinear. Use complete sentences to describe the sum of CA (straight line abov

blsea [12.9K]

A is the midpoint of line CB. This means that CA + AB = CB.

3 0

3 years ago