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Shkiper50 [21]
3 years ago
13

50 POINTS

Chemistry
1 answer:
Marina86 [1]3 years ago
8 0

Answer:

A mixture whose components are soluble in each other. ... a solution that has water as its solvent; most have an ionic substance as the solute, may contain a liquid ... The suspensions of particles larger than individual ions or molecules, but the ... This effect is used to determine whether a mixture is a true solution or a colloid.

process of solute particles being surrounded by water molecules arranged in a ... solution. homogeneous mixture consisting of a solute dissolved into a solvent. ... apart from the crystal, the individual ions are then surrounded by solvent particles in a ... are intermediate in size between those of a solution and a suspension.

A suspension is a heterogeneous mixture in which some of the particles ... The particles in a suspension are far larger than those of a solution, so gravity is … ... Particle size: 0.01-1nm; atoms, ions or molecules, Particle size: ... solutions because the individual dispersed particles of a colloid cannot be seen.

Explanation:

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Does my sister fart CCCCCCCCCCCCAAAAAAAAAAAAAAAAAAANNNNNNNNNNNNNNNNNNN YYYYYYYYYYYYYYYYYYYYYYYYYYOOOOOOOOOOOOOOOOOOOOOOOOOOOOOUU
Zinaida [17]

Yes she does. And it probably smells

7 0
4 years ago
Read 2 more answers
What is the conservation of mass
adelina 88 [10]

Answer: This is the definition if that's what you want.

Explanation:The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as system's mass cannot change, so quantity can neither be added nor be removed.

8 0
3 years ago
Which of the following illustrates the conservation of matter? A. SnO2 + H2 --> Sn + 2 H2O B. 2 C + O2 --> CO2 C. KOH + HB
olga2289 [7]

C. KOH + HBr → KBr + H₂O

Explanation:

The two equations above illustrates the conservation of matter. The law of conservation of matters states that

               "in a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".

By this law, we understand that the amount of a particular matter we are starting with should be the one we end with.

    KOH + HBr → KBr + H₂O

Conserving                          Product                          Reactants

     K                                         1                                           1

     O                                         1                                           1

      H                                         2                                          2

We can see that the amount on both sides are the same.

Learn more:

Conservation of matter brainly.com/question/2190120

#learnwithBrainly

8 0
3 years ago
Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con
anyanavicka [17]

Answer:

0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 }  *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O}  *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

5 0
3 years ago
2. The reaction of zinc with nitric acid was carried out in a calorimeter. This reaction caused the temperature
snow_lady [41]

We want to solve Q = mcΔT for the liquid water; its change in temperature will tell us the amount of thermal energy that flowed out of the reaction. The specific heat, c, of water is 4.184 J/g °C.

Q = (72.0 g)(4.184 J/g °C)(100 °C - 25 °C) = 22593.6 J

Q ≈ 2.26 × 10⁴ J or 22.6 kJ (three significant figures).

3 0
3 years ago
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