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uranmaximum [27]
3 years ago
12

A gold-colored ring has a mass of 17.5 grams and a volume of 0.82 mL. What is the density of this ring?

Chemistry
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

21 g/mL

Explanation:

To solve this problem, first look at the density equation, which is D=M/V, which D stands for density, M stands for mass, and V stands for volume. When you substitute in the variables, you get D=17.5/.82, which is equivalent to 21.34. However, since we need to pay attention to the sig fig rules for multiplying, we need to have the same amount of sig figs as the value with the least amount of sig figs, which is the number .82. .82 has two sig figs, so you round down. Your answer will be 21 g/mL.

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what is the boiling point of a 0.321 m aqueous solution of NaCl. Enter your rounded answer with 3 decimal places.
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bija089 [108]

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(a) At constant volume condition the entropy change of the gas is:

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As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

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Now we have to calculate the entropy change of the gas.

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(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

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Minchanka [31]

Answer:B

Explanation:

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3 years ago
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