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Zanzabum
3 years ago
7

What is physical and chemical change ?

Chemistry
1 answer:
galben [10]3 years ago
4 0

Answer:

Physical change is there is a difference in appearance, smell, etc.

Chemical change is there is change in the composition or the rearrangement of the atoms of one or more substances.

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What type of solid is candle wax ? Amorphous or Crystalline?
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<span>It is amorphous because it gets softer and softer, and it doesn't melt at a distinct temperature.

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In the reaction of nitrogen gas with oxygen gas to produce nitrogen oxide, what is the effect of adding more oxygen gas to the i
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<h3>Answer:</h3>

The Equilibrium would shift to produce more NO

<h3>Explanation:</h3>

The reaction is;

N₂(g) + O₂(g) ⇆ 2NO(g)

  • When a reaction is at equilibrium then the forward reaction rate will be equivalent to the reverse reaction rate. Additionally, the concentration of the reactants and products are the same.
  • From Le Chatelier's principle, additional reactants favor the formation of more products while additional products favor the formation of more reactants.
  • For example, when more oxygen is added then more Nitrogen (II) oxide will be formed.
  • Oxygen is a reactant and when increased it favors forward reaction which leads to the formation of more NO which is the product.

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3 years ago
What is a spectator ion?
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<span>A spectator ion is an ion that exists in the same form on both the reactant and product sides of a chemical reaction.</span>
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3 years ago
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As the movement of molecules within a substance increases, describe the change in heat of the substance. Justify your response i
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It will get hotter, because the molecules create heat when they move around just like us when we run.
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N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f
kow [346]

Answer : The final concentration of N_2O_5 is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.89\times 10^{-3}\text{ min}^{-1}

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}

a-x=2.9M

Thus, the final concentration of N_2O_5 is, 2.9 M

3 0
2 years ago
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