Answer:
i think the answer is B cus i think of that
Atomic or hybrid orbital on the central br atom makes up the sigma bond between this br and an outer f atom in bromine trifluoride, brf3 is sp2 hybridization
Trigonal hybridization is another name for sp2 hybridization. It entails combining one's' orbital with two 'p' orbitals of equal energy to create a new hybrid orbital known as sp2. A trigonal symmetry combination of s and p orbitals that is kept at 120
One of the hybrid orbitals formed when one s orbital and two p orbitals are mathematically merged to form three new equivalent orbitals orientated toward the corners of a triangle is sp2 hybridization.
The only feasible molecule geometry for sp2 hybridized center atoms is trigonal planar. When all of the bonds are in place, the shape is trigonal planar as well.
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C) A yellow precipitate settles to the bottom.
Explanation:
Lead nitrate is reacting with potassium iodide to form lead iodide, which is a yellow precipitate, and potassium nitrate.
Pb(NO₃)₂ (aq) + KI (aq) → PbI₂ (s) + KNO₃ (aq)
where:
(aq) - aqueous
(s) - solid
A) The solution is yellow.
False, the solution is colorless while the PbI₂ precipitate is yellow.
B) Both reactants are aqueous solutions.
True, however this is not a proof that the chemical reaction occurred.
C) A yellow precipitate settles to the bottom.
True and this is a proof that the chemical reaction occurred because of the formation of PbI₂ yellow precipitate.
D) Lead and potassium are both metals and will replace each other.
True, but this is not a proof that the chemical reaction occurred.
Learn more about:
types of chemical reactions
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Answer:
A) when the titration is nearing the end point in titration the color of the solution starts to change and the change in color does not disappear as fast as it was during the beginning of the titration
B) The volume of NaOH required to permanently change the indicator at the end point is a drop of NaOH
c) The volume required by samples #2 and #3 will be the same i.e 19.90 mL of NaOH, if the concentration of KHP base used for the samples are the same
D) The volume required by samples #2 and #3 will be the same i.e 29.05 mL OF NaOH, if the concentration of Vinegar and base for the samples are the same
Explanation:
A) when the titration is nearing the end point in titration the color of the solution starts to change and the change in color does not disappear as fast as it was during the beginning of the titration
B) The volume of NaOH required to permanently change the indicator at the end point is a drop of NaOH
c) The volume required by samples #2 and #3 will be the same i.e 19.90 mL of NaOH, if the concentration of KHP base used for the samples are the same
D) The volume required by samples #2 and #3 will be the same i.e 29.05 mL OF NaOH, if the concentration of Vinegar and base for the samples are the same
