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Gnesinka [82]
4 years ago
11

Dry ice is solid carbon dioxide. A 1.65−g sample of dry ice is placed in an evacuated 3.93−L vessel at 23.0°C. Calculate the pre

ssure inside the vessel after all the dry ice has been converted to CO2 gas.
Chemistry
1 answer:
shusha [124]4 years ago
4 0

<u>Answer:</u> The pressure of the gas inside the vessel is 0.232 atm

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of carbon dioxide = 1.65 g

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

\text{Moles of carbon dioxide}=\frac{1.65g}{44g/mol}=0.0375mol

To calculate the pressure of the gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = ?

V = Volume of the gas = 3.93 L

T = Temperature of the gas = 23^oC=[23+273]=296K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of gas = 0.0375 moles

Putting values in above equation, we get:

P\times 3.93L=0.0375mol\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 296K\\\\P=\frac{0.0375\times 0.0821\times 296}{3.93}=0.232atm

Hence, the pressure of the gas inside the vessel is 0.232 atm

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Explanation:

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What oxidation state(s) can the alkaline earth metals exhibit?
iragen [17]

Answer:

+2

Explanation:

Alkaline earth metals are present in group 2 of periodic table. There are six elements in second group. Beryllium, magnesium, calcium, strontium, barium and radium.

All have two valance electrons.

Electronic configuration of Beryllium:

Be = [He] 2s²

Electronic configuration of magnesium.

Mg = [Ne] 3s²

Electronic configuration of calcium.

Ca = [Ar] 4s²

Electronic configuration of strontium.

Sr = [Kr] 5s²

Electronic configuration of barium.

Ba = [Xe] 6s²

Electronic configuration of radium.

Ra = [ Rn] 7s²

They are present in group two and have same number of valance electrons (two valance electrons) and show oxidation state +2 by loosing two valance electrons. They also show similar reactivity.

They react with oxygen and form oxide.

2Ba   +   O₂   →    2BaO

2Mg  +   O₂   →    2MgO

2Ca +   O₂   →    2CaO

this oxide form hydroxide when react with water,

BaO  + H₂O   →  Ba(OH)₂

MgO  + H₂O   →  Mg(OH)₂

CaO  + H₂O   →  Ca(OH)₂

With sulfur,

Mg + S   →  MgS

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Explanation:

many hazardous chemicals are also classified as dangerous goods.

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dimaraw [331]

Answer:

0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).

Explanation:

  • Knowing that:

<em>d = m/V,</em>

where, d is the density of the material (g/cm³).

m is the mass of the material (m = 28 g).

V is the volume of the material (V = 63.0 cm³).

<em>∴ d = m/V </em>= (28 g)/(63.0 cm³) = <em>0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).</em>

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