Answer : The equilibrium will shift in the left direction.
Explanation :
Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
The given reaction is:

As per question, when we are adding
then the concentration of
is increased on product side then the equilibrium will shift in the direction where decrease of concentration of
takes place. Therefore, the equilibrium will shift in the left direction.
Thus, the equilibrium will shift in the left direction.
Answer:
This flexible ability is important because it allows the cell to survive in differing environments, such as when immersed in water over long periods of time.
With your mind. Boom. Lol I'm sorry I don't know I just need points
Answer:

Explanation:
We are asked to find the volume of a solution given the moles of solute and molarity.
Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.
- moles of solute = 0.14 mol KCl
- molarity= 1.8 mol KCl/ L
- liters of solution=x
Substitute these values/variables into the formula.

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.



Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.


The units of moles of potassium chloride cancel.


The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

There are approximately <u>0.078 liters of solution.</u>
Answer:
12120 g + O2 = 15084 g
m Zn = 12.120 Kg
m óxido = 15.084 Kg
1. calcular la masa de cinc en gramos
g = 12,120 Kg x 1000 = 12120 g de cinc
g = 15.084 Kg x 100 = 15084 g de oxígeno
2. calcular gramos de Oxigeno
g O = 15084 g - 12120 g = 2964 g O2
3. calcular % de Zn y O
%m/m ( m soluto / m solc.) x 100
%m/m (Zn) = ( 1210 g / 15084 g ) x 100
% m/m (Zn) = 80.35 % = 80.35 g
%m/m (O) = ( 2964 g / 15084 g ) x 100
% m/m (Zn) = 19.65 % = 19.65 g
4. Calcular moles de cada elemento
Zn: 80.35 g / 65.38 g/mol = 1.228 mol
O: 19.65 g / 16 g/mol = 1.228 mol
5. dividir entre el menor de los elementos
Zn: 1.228 mol / 1.228 mol = 1
O: 1.228 mol / 1.228 mol = 1
6. Fórmula empírica: ZnO