<u>Answer:</u> The pressure of the gas inside the vessel is 0.232 atm
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of carbon dioxide = 1.65 g
Molar mass of carbon dioxide = 44 g/mol
Putting values in above equation, we get:

To calculate the pressure of the gas, we use the equation given by ideal gas which follows:
PV=nRT
where,
P = pressure of the gas = ?
V = Volume of the gas = 3.93 L
T = Temperature of the gas = ![23^oC=[23+273]=296K](https://tex.z-dn.net/?f=23%5EoC%3D%5B23%2B273%5D%3D296K)
R = Gas constant = 
n = number of moles of gas = 0.0375 moles
Putting values in above equation, we get:

Hence, the pressure of the gas inside the vessel is 0.232 atm