The amount of heat needed to cook the pork roast is 1700 kJ.
The amount of heat absorbed by the roast is 14% of the heat produced = 14% X ?H = 310.38 kJ/mol
One mole of propane burns to produce 3 moles of CO2 and -2217 kJ of heat.
1700kJ/ (14% X ?H) = mol of C3H8 burned
1700kJ / (310.38 kJ/mol) = 5.48 mol C3H8
Since 3 moles of CO2 are produced:
3 X 5.48 mol= 16.43 mols of CO2
convert moles to grams:
16.43 mol CO2 X 44.0g/mol ~ 722.9 g CO2 produced
Answer:
B. High optical density, and light travels more slowly through it.
Step-by-step explanation:
Refractive index is the property of a material that describes the change in the initial path of light and the rate at which light travels through it. And optical density of a material describes its absorption ability to rays or beam of light passing through it.
As the index of refraction of a material increases, therefore its optical density would increase. This would cause light to travel through it slowly. Unless the light has a high frequency.
A material with a high index of refraction has a high optical density, and light travels more slowly through it.
25-16=9
9+23=32
He had 32 CDs to begin with
