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melisa1 [442]
3 years ago
15

Please help me this is due today!

Mathematics
2 answers:
frozen [14]3 years ago
8 0

If opposite means negative, then the answer would be - 1 1/2.

ra1l [238]3 years ago
5 0

Answer:

the answer is "d" i believe

Step-by-step explanation:

the opposite of a positive is a negative and it says "write your answer as a mixed number"

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xxMikexx [17]
THE answer is D i hope it is correct
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A 96-ounce container of orange juice costs$4.80. At what price should a 128-ounce container be sold in order for the unit rate f
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$7.48

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3 years ago
What is the value of f(−1) when f(x)=2x+2
mart [117]

Answer:

<h2>f( - 1) = 0</h2>

Step-by-step explanation:

f(x)=2x+2

To find f(−1) , substitute the values of x that's - 1 into f(x). That is for every x in f(x) replace it with - 1

That's

f( - 1) = 2( - 1) + 2 \\  =  - 2 + 2

We have the final answer as

f( - 1) = 0

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7 0
3 years ago
Help pls, will mark brainliest
BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be {\sf T_n} is given by ;

  • {\boxed{\bf T_{n}=T_{1}+(n-1)d}}

Where , <u>d</u> is the common difference

Now , here we are given with ;

{\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

{: \implies \quad \sf T_{1}+(5-1)d=T_{5}}

Putting the values and transposing 1st term to RHS , we have ;

{: \implies \quad \sf 4d = -4-8}

{: \implies \quad \sf d=-\dfrac{12}{4}}

{: \implies \quad \sf d=-3}

Now , as we got the common difference , so we can find out the missing terms now ;

{: \implies \quad \sf T_{2}= T_{1}+(2-1)d}

{: \implies \quad \sf T_{2}= 8 +d}

{: \implies \quad \sf T_{2}= 8-3}

{: \implies \quad \bf \therefore \:  T_{2}= 5}

Now

{: \implies \quad \sf T_{3}= T_{1}+(3-1)d}

{: \implies \quad \sf T_{3}= 8 +2d}

{: \implies \quad \sf T_{3}= 8-6}

{: \implies \quad \bf \therefore \:  T_{3}= 2}

Also ,

{: \implies \quad \sf T_{4}= T_{1}+(4-1)d}

{: \implies \quad \sf T_{4}= 8 +3d}

{: \implies \quad \sf T_{4}= 8-9}

{: \implies \quad \bf \therefore \:  T_{4}= -1}

Now , The given table can be written as ;

{\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

8 0
3 years ago
Each of the line segments in the word MATH are numbered in the graph below. Find the slope (as a ratio of rise over run) of each
emmasim [6.3K]

Answer/Step-by-step explanation:

7. Line 1 = undefined.

Slope of a vertical line is always undefined. The run is zero as x-coordinate remains the same.

8. Line 2 = \frac{4}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 4}{-5 -(-8)}

slope = \frac{8 - 4}{-5 + 8}

slope = \frac{4}{3}

9. Line 3 = \frac{4}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 4}{-2 -(-5)}

slope = \frac{8 - 4}{-2 + 5}

slope = \frac{4}{3}

10. Line 4 = undefined (slope of a vertical line is always undefined)

11. Line 5 = \frac{7}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 1}{5 - 2}

slope = \frac{7}{3}

12. Line 6 = -\frac{7}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 1}{5 - 8}

slope = \frac{7}{-3}

slope = -\frac{7}{3}

13. Line 7 = 0

An horizontal line has no rise.

14. Line 8 = 0 (slope of horizontal line is always zero)

15. Line 9 = undefined (slope of a vertical line is always undefined)

16. Line 10 = undefined (slope of a vertical line is always undefined)

17. Line 11 = 0 (slope of horizontal line is always zero)

18. Line 12 = undefined (slope of a vertical line is always undefined)

5 0
3 years ago
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