To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Answer:
What statements?
Step-by-step explanation:
Step-by-step explanation:
7 1/2 = 7 + 1/2 = 14/2 + 1/2 = 15/2 = 7.5
check the attached picture.
:)
Answer:
HCF=2*2=4
Step-by-step explanation:
Given : Shane wants to plant 28 marigold plants and 36 rose plants in his garden
To Find : the greatest number of rows possible each row has the same
number of marigold plants and the same number of rose plants.
Solution:
marigold plants = 28
rose plants = 36
To find the greatest number of rows possible if each row has the same
number of marigold plants and the same number of rose plants.
we need to find HCF of 28 and 36
28 = 2 x 2 x 7
36 = 2 x 2 x 3 x 3
HCF = 2 x 2 = 4
greatest number of rows possible is 4
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If the HCF of (p²-p-6) and (p²+3p-18) is (p-a). Find the value of a ...
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Answer: 3/20
Step-by-step explanation:
12/80 is simplified to 3/20