Answer:
To be done in time, he would need to solve 6 questions per day on the days that he is not on trip 
Step-by-step explanation:
If he solves the problems 5 per day, the total number of days that would be required to finish solving the problem would be 120/5 = 24 days 
Now, he has 4 free days which would be for a family trip. The number of questions that he would miss during those trip days will be 4 * 5 = 20 questions 
Now since he wants to still finish on time, what is needed to be done is to share the 20 left overs amongst the 20 days which he has to work 
This makes a total of 1 question per day 
Adding this to the 5 questions per day he has before will be = 6 questions per day 
 
        
             
        
        
        
Answer:
The answer is

Step-by-step explanation:
To find an equation of a line given the slope and a point we use the formula

where
m is the slope
( x1 , y1) is the point
From the question the point is (−5, 6) and slope = 3
The equation of the line is 

We have the final answer as

Hope this helps you
 
        
                    
             
        
        
        
Answer:
its b
Step-by-step explanation:
i did this
 
        
                    
             
        
        
        
(-2, 0) and (0, -2)
slope = (0+2)/(-2 - 0) = -1
b = -2
slope intercept equation
y = -x - 2
compare equation from given
y - 3 = -(x + 5)
y - 3 = -x - 5
y = -x - 5 + 3
y = -x - 2 (matched slope intercept equation)
answer is A
y - 3 = -(x + 5)
        
                    
             
        
        
        
The length of the rectangle is = 72 cm
The width of the rectangle is = 56 cm
Area of the rectangle is = 
=  cm²
 cm²
As given, the other rectangle has the same area as this one, but its width is 21 cm. 
Let the length here be = x


Hence, length is 192 cm.
We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.
So, in the new rectangle,constant of variation=k is given by,
 or
 or 
Hence, the constant of variation is 