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Igoryamba
3 years ago
12

What happens to mass and energy in a closed system?

Chemistry
1 answer:
fredd [130]3 years ago
8 0

Answer:

the correct answer is D. Both energy and mass can enter or exit a closed system.

Explanation:

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Which is the greater distance 50 miles or 100 kilometers
slega [8]
The greater distance is 50 miles
4 0
3 years ago
Provide an appropriate alkyne starting material A and intermediate product B. Omit byproducts. The number of carbon atoms in the
nadezda [96]

Answer:

C4H6 + 2HBr = C4H8Br2

Explanation:

Alkynes are organic molecules made of the functional group carbon-carbon triple bonds and are written in the empirical formula of CnH2n−2. They are unsaturated hydrocarbons.

Furthermore, Halogenation reaction of any alkyne such as but-2-yne with any of the hydro halogenated compounds such as HBr, HCl, HF or HI will give an alkane that will have the same number of carbon atoms in the starting material and in the final product.

Halogenation reaction is a reaction that occurs when one or more halogens are added to a substance. Halogens is the seventh column in the periodic table and it include fluorine, chlorine, bromine, iodine, and astatine.

6 0
3 years ago
I need help! Thanks!
Tems11 [23]

Answer:

C. As speed increases, kinetic energy increase exponentially

Explanation:

As you can see on the graph, the further right we move on the x-axis, the higher the values on the y-axis. This means that as one value increases, the other value also increases. The only answer choice that says this is C.

Hope this helps :)

4 0
3 years ago
Read 2 more answers
1. Which is not true of binary compounds?
nignag [31]
Pretty sure it's b but not an definitely
4 0
3 years ago
Read 2 more answers
Consider the data presented below. time (s) 0 40 80 120 160 moles of a 0.100 0.067 0.045 0.030 0.020 part a part complete determ
Whitepunk [10]
To determine which order of the reaction it is, first we need to calculate the rate of change of moles.
the data is as follows 
time         0         40        80       120       160
moles    0.100   0.067  0.045    0.030    0.020


Q1)
for the first 40 s change of moles ;
      = -d[A] / t
      = - (0.067-0.100)/40s
      = 8.25 x 10⁻⁴ mol/s
for the next 40 s
      = -(0.045-0.067)/40
      = 5.5 x 10⁻⁴ mol/s
the 40 s after that
      = -(0.030-0.045)/40 s 
     = 3.75 x 10⁻⁴ mol/s
k - rate constant
and A is the only reactant that affects the rate of the reaction

rate = k [A]ᵇ
8.25 × 10⁻⁴ mol/s = k [0.100 mol]ᵇ ----1
5.5 x 10⁻⁴ mol/s = k [0.067 mol]ᵇ   -----2
divide the 2nd equation by the 1st equation
1.5 = [1.49]ᵇ
b is almost equal to 1
Therefore this is a first order reaction

Q2)
to find out the rate constant(k), we have to first state the equation for a first order reaction.
rate = k[A]ᵇ
As A is the only reactant thats considered for the rate equation. 
Since this is a first order reaction,
b = 1
therefore the reaction is 
rate = k[A]
substituting the values,
8.25 x 10⁻⁴ mol/s = k [0.100 mol]
k = 8.25 x 10⁻⁴ mol/s /0.100mol
   = 8.25 x 10⁻³ s⁻¹

7 0
3 years ago
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