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marta [7]
3 years ago
11

An object is thrown with a horizontal velocity of 49.0 mt/sec and a vertical velocity 18.8 mt/sec. How long with the object take

to reach its maximum height and start to return to the earth? Please help asap
Physics
2 answers:
UNO [17]3 years ago
7 0

Answer:

49.0 x18.8 ur answer i think

Explanation:

BabaBlast [244]3 years ago
5 0

Answer:

49.0

Explanation:

yes. n.y ecj he rtk hgt gum kg FL kit rhyl kit full gd

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What will be the weight of a man of mass 90kg when he is on a planet with acceleration due to gravity of 15ms-2?
Feliz [49]

Answer:

1350N

Explanation:

Weight = Mass x Acceleration Due to Gravity

W=mg

W=90*15=1350N

7 0
3 years ago
One difference between a hypothesis and a theory is that a hypothesis
artcher [175]
A hypothesis is a tentative statement which is made to try to explain a known phenomenon but whose truth value is still uncertain, whether it is true or no depends on further research. On the other hand, a theory is made up of hypothesis which have been proven to be true so far, a theory should be able to explain future phenomena successfully
3 0
3 years ago
A gold bar has a density of 19.3 g/mL. If the gold bar has a mass of 6.3 grams, what is the volume?
Natali [406]

Answer:

The correct answer is "0.32 mL".

Explanation:

The given values are:

Density of gold bar,

d = 19.3 g/mL

Mass of gold bar,

m = 6.3 grams

Now,

The volume will be:

⇒  Density = \frac{Mass}{Volume}

or,

⇒  Volume=\frac{Mass}{Density}

On substituting the values, we get

⇒               =\frac{6.3 \ g}{19.3 \ g/mL}

⇒               =0.32 \ mL

7 0
3 years ago
A projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity
Viktor [21]

Answer:

-26 m/s.

Explanation:

Hello,

In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:

t=\frac{0m/s-26m/s}{-9.8m/s^2} =2.65s

With which we compute the maximum height:

y=26m/s*2.65s-\frac{1}{2}*9.8m/s^2*(2.65s)^2 \\\\y=34.5m

Therefore, the final velocity until the floor, assuming P as the starting point (Voy=0m/s), turns out:

v_f=\sqrt{0m/s-(-9.8m/s^2)*2*34.5m}\\ \\v_f=-26m/s

Which is clearly negative since it the projectile is moving downwards the starting point.

Regards.

3 0
3 years ago
Two long, straight wires are parallel and 20 cm apart. One carries a current of 2.2 A, the other a current of 5.9 A. (a) If the
Leya [2.2K]

Answer: 1.298\times 10^{-5}\ N/m

Explanation:

Given

Current in the first wire I_1=2.2\ A

Current in the second wire I_2=5.9\ A

wires are 20\ cm apart

Force per unit length between the current-carrying wires is

\Rightarrow \dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}

Force exerted  by the wires is the same

Put the values

\Rightarrow \frac{F}{l}=f=\dfrac{4\pi \times 10^{-7}\times 2.2\times 5.9}{2\pi \times 0.2}=1.298\times 10^{-5}\ N/m

This force will be repulsive in nature as the current is flowing opposite

4 0
3 years ago
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