All categories

3 years ago

Only people who are better than me can answer this ( ◜‿◝ )♡

Physics

2 answers:

Alex777 [14]3 years ago

7 0

Answer:

Solution: If two liquid drops coalesce then there will be a decrease in surface area, simultaneously there will be a decrease in surface energy hence energy is liberated.

Explanation:

What i mean is basically 2

baherus [9]3 years ago

5 0

energy is evolved ....ig

You might be interested in

Que es la energia electrica

Mnenie [13.5K]

Answer:

:) :) :) :) :) :) :) :) :)

Explanation:

:) :) :) .......

6 0

3 years ago

Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.

scoundrel [369]

Answer

Pressure, P = 1 atm

air density, ρ = 1.3 kg/m³

a) height of the atmosphere when the density is constant

Pressure at sea level = 1 atm = 101300 Pa

we know

P = ρ g h

$h = \dfrac{P}{\rho\ g}$

$h = \dfrac{101300}{1.3\times 9.8}$

h = 7951.33 m

height of the atmosphere will be equal to 7951.33 m

b) when air density decreased linearly to zero.

at x = 0 air density = 0

at x= h ρ_l = ρ_sl

assuming density is zero at x - distance

$\rho_x = \dfrac{\rho_{sl}}{h}\times x$

now, Pressure at depth x

$dP = \rho_x g dx$

$dP = \dfrac{\rho_{sl}}{h}\times x g dx$

integrating both side

$P = g\dfrac{\rho_{sl}}{h}\times \int_0^h x dx$

$P =\dfrac{\rho_{sl}\times g h}{2}$

now,

$h=\dfrac{2P}{\rho_{sl}\times g}$

$h=\dfrac{2\times 101300}{1.3\times 9.8}$

h = 15902.67 m

height of the atmosphere is equal to 15902.67 m.

6 0

3 years ago

Jon recently drove to visit his parents who live 648 miles away. On his way there his average speed was 14 miles per hour faster

Vladimir79 [104]

Answer:

speed of the Jon visiting parents = 56 mph

speed of the Jon when returning from home = 56 - 14 = 42 mph

Explanation:

given,

distance of Jon parent's house = 648 mile

avg speed when he was visiting his parent's house be 'x' mph

avg speed when he is returning from his parent's house be 'x-14' mph

total time taken = 27 hours

total distance = speed × time

648 = x × t₁

$t_1 = \dfrac{648}{x}$

648 = ( x - 14 ) × t₂

$t_2 = \dfrac{648}{x-14}$

t = t₁ + t₂

$27 = \dfrac{648}{x} + \dfrac{648}{x-14}$

$1 = 24 (\dfrac{1}{x} + \dfrac{1}{x-14})$

x² - 62 x + 336 = 0

x² - 56 x - 6 x + 336 = 0

(x - 56 )(x - 6)=0

on solving

x = 56 ,6

hence, speed of the Jon visiting parents = 56 mph

speed of the Jon when returning from home = 56 - 14 = 42 mph

8 0

3 years ago

Read 2 more answers

A current of 0.96 amps flows through a copper wire 0.44 mm in diameter when connected to a potential difference of 15 v. how lon

FinnZ [79.3K]

By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:
$V=IR$
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
$R= \frac{V}{I}= \frac{15 V}{0.96 A}=15.6 \Omega$

Now we can use the following equation to calculate the length of the wire:
$R= \frac{\rho L}{A}$ (1)
where
$\rho$ is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity $\rho=1.68 \cdot 10^{-8} \Omega m$ . The radius of the wire is half the diameter:
$r= \frac{d}{2}= \frac{0.44 mm}{2}=0.22 mm=0.22 \cdot 10^{-3} m$
And the cross-sectional area is
$A=\pi r^2=\pi (0.22 \cdot 10^{-3}m)^2=1.52 \cdot 10^{-7} m^2$

So now we can rearrange eq.(1) to calculate the length of the wire:
$L= \frac{RA}{\rho}= \frac{(15.6 \Omega)(1.52 \cdot 10^{-7} m^2)}{1.68 \cdot 10^{-8} \Omega m}=141.1 m$

8 0

3 years ago

Estimate how fast your hair grows, in units of m/s, assuming it takes 30 days for your hair to grow 1 inch. note that 1 inch =2.

VashaNatasha [74]

Answer:

1. 9.8 x 10^-7 cm/s

2. 50970 L

Explanation:

time, t = 30 days = 30 x 24 x 60 x 60 seconds = 2592000 seconds

length of hair, d = 1 inch = 2.54 cm

rate of growth = length of hair grows per second = 2.54 / 2592000

= 9.8 x 10^-7 cm/s

Thus, the grown rate of hair is 9.8 x 10^-7 cm/s.

2. length of the pool, l = 15 feet

width of the pool, w = 15 feet

height of pool, h = 8 feet

Volume of the pool, V = length x width x height

V = 15 x 15 x 8 = 1800 ft^3

To convert ft^3 into m^3 , we use

1 ft = 0.3048 m

so, 1 ft^3 = (0.3048)^3 m^3 = 0.0283 m^3

So, 1800 ft^3 = 1800 x 0.0283 = 50.97 m^3

now, 1 m^3 = 1000 L

So, 50.97 m^3 = 50.97 x 1000 L = 50970 L

3 0

3 years ago

Only people who are better than me can answer this ( ◜‿◝ )♡​

Only people who are better than me can answer this ( ◜‿◝ )♡