Answer:Moles of Mg, Cl, 0 = 5.40, 10.80, 43.2
Explanation:
1 mole of Mg(ClO4)2 contains 1 mole of Magnesium, Mg atoms
2 Moles of Chlorine, Cl atoms
8 Molresof Oxygen atoms
Such that to find the number of moles of each element, We have that
------1 mole Magnesum atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 1 x 5.40 =5.40 moles
------2 moles ofChlorine atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 2 x 5.40 = 10.80 moles
------8 moles Oxygen atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 8 x 5.40 = 43.2 moles
0.02 grams/ mL to grams/L would be 20 grams/Liter
Answer:
44.8L of hydrogen gas
Explanation:
The reaction expression is given as:
2Na + 2H₂O → 2NaOH + H₂
Given parameters:
Mass of sodium = 92.4g
Unknown:
Volume of hydrogen gas = ?
Solution:
To solve this problem:
1 mole of a substance at STP occupies a volume of 22.4L
Let us find the number of moles of the hydrogen gas;
Number of moles of Na = 
Molar mass of Na = 23g/mol
Number of moles = 
= 4.02mole
From the balanced reaction expression:
2 mole of Na will produce 1 mole of hydrogen gas
4.02 mole of Na will produce 
= 2mole of hydrogen gas
So
1 mole of a substance at STP occupies a volume of 22.4L
2 mole of hydrogen gas will occupy a volume of 2 x 22.4 = 44.8L of hydrogen gas
Answer:
mechanical energy to electrical energy
Explanation:
The water turns the turbine with produces mechanical energy so the generator converts it to electrical energy
Answer:
152.4 g of O₂ are consumed.
Explanation:
We start from the combustion reaction:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We convert the mass of propane to moles:
41.9 g . 1mol /44g = 0.952 moles
Ratio is 1:5. 1 mol of propane consumes 5 moles of oxygen at propane combustion
Then, 0.952 moles may consume (0.952 . 5) /1 = 4.76 moles.
We convert moles to mass → 4.76 mol . 32g/mol = 152.4 g
