Answer:
p(a) * p(b) = .01923
p(b) = .01923 / .07692 = .2500
Answer:
I think that the answer might be d
Icecaps that are dissolving, a system of canal-like geometric features, and various pitch black surface markings are all thought to be vegetation are the observations of the martian surface led Lowell to the conclusion that intelligent life forms existed on Mars.
<h3>What is a solar system?</h3>
It is a system that collection of all the planets and spatial bodies revolving around the sun because of the gravitational pull of the sun.
Our Solar System is based on a heliocentric model in which the Sun is assumed to reside at the central point of the planetary system.
In other words, the Sun is at the center while the Earth and other planetary bodies revolve around it.
Lowell came to the conclusion that intelligent life existed on Mars based on his observations of the martian surface, which included melting icecaps, a network of geometric patterns that resemble canals, and numerous markings on the completely black surface that are believed to be flora.
Learn more about Solar systems from here,
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To solve this problem we will apply the definitions given in Newtonian theory about the Force of gravity, and the Force caused by weight. Both will be defined below, and in equal equilibrium condition to clear the variable concerning acceleration due to gravity. Finally, with the values provided in the statement, it will be replaced.
The equation for the gravitational force between the Earth and the object on the surface of the Earth is

Where,
G = Universal gravitational constant
= Mass of Earth
= Distance between object and center of earth
= Mass of Object
The equation for the gravitational pulling force on the object due to gravitational acceleration is

Equation the two expression we have


This the acceleration due to gravity which is composite constant.
Replacing with our values we have then


The value of composite constant is
. Here, the composite constant is nothing but the acceleration due to gravity which is constant always.