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DIA [1.3K]
3 years ago
15

a device employing a lens, shutter, and persistent light source that projects images from glass slides onto a flat white wall or

cloth drape hung in the dark is _______
Physics
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

The answer is a projector

Explanation:

A projector is an output device that projects an image onto a large surface, such as a white screen or wall. It may be used an alternative to a monitor or television when showing video or images to a large group of people, mostly at functions, events, seminars, presentations.

seraphim [82]3 years ago
6 0

A device employing a lens, shutter, and persistent light source that projects images from glass slides onto a flat white wall or cloth drape hung in the dark is image projection began with the MAGIC LANTERN

<h3><u>Explanation:</u></h3>

The magic lantern works on the sliding runner technology. The image can be made larger in size and can be projected with the help of an optical device. When the technology of motion toy become older, this magic lantern is the modernized version of the motion toy technology. The modernization of the magic lantern was as an alternative of to motion-toy technology.

The photos and images that are taken can be increased in the size and projection can be made. These images can be enlarged in size by the help of a photographic images. this helps in image and also in taking photographs. This photographic image can be attached with Magic lantern. A long slide of glass helps in projecting the image on the walls or cloth drapes using magic lantern. This gives life to Shadows.

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A piece of zinc was lying outside and had a temperature of 26 degrees C. Later that day the sun came out and the temperature inc
pickupchik [31]

Answer:

570 J

Explanation:

im sorry im not sure about the rest but i hope this helps

3 0
3 years ago
A plane on the ground will weigh:
kenny6666 [7]

On ground weight of plane will be measured as its actual weight which will be given as

W = mg

now when plane is in air its weight is measured as combined effect of earth gravitational force and buoyancy force both

so weight in air will be given as

W_{air} = mg - F_b

here since net effect due to air is opposite to the direction of weight so in air the plane weight will be measure less than its weight on ground.

so answer will be

A)more than a plane in the air

3 0
3 years ago
Read 2 more answers
A 2.2 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
iogann1982 [59]

Answer:

a) k = 2851.2\,\frac{N}{m}, b) v = 0.54\,\frac{m}{s}

Explanation:

a) According to the Principle of Energy Conservation, the kinetic energy of the box is transformed into elastic potential energy.

\frac{1}{2}\cdot (2.2\,kg)\cdot (1.8\,\frac{m}{s} )^{2} = \frac{1}{2}\cdot k \cdot (0.05\,m)^{2}

The spring constant is:

k = 2851.2\,\frac{N}{m}

b) The initial speed needed to compress the spring by 1.5 centimeters is:

\frac{1}{2}\cdot (2.2\,kg)\cdot v^{2} = \frac{1}{2}\cdot (2851.2\,\frac{N}{m} )\cdot (0.015\,m)^{2}

v = 0.54\,\frac{m}{s}

5 0
4 years ago
Using a horizontal force of 200N,we intend to move a wooden cabinet across a floor at constant velocity.What is the friction for
IgorLugansk [536]

Answer:

-200 N

Explanation:

The cabinet moves at constant velocity, so that means there's no acceleration.

Applying Newton's second law to the cabinet:

∑F = ma

F + 200 = 0

F = -200

The friction force is 200 N in the opposite direction.

8 0
3 years ago
3/122 The collar has a mass of 2 kg and is attached to the light spring, which has a stiffness of 30 N/m and an unstretched leng
gavmur [86]

Explanation:

According to the law of conservation of energy, work done by the force is as follows.

        W_{F} = F Cos (30^{o}) \times 1.5

                   = 64.95 J

Now, gain in potential energy is as follows.

                P.E = mgh

                      = 2 \times 9.8 \times 1.5

                      = 29.4 J

Gain in potential energy will be as follows.

           = \frac{1}{2}kx^{2}_{2} - \frac{1}{2}kx^{2}_{1}

           = \frac{1}{2} \times 30 N/m \times [(2.5 - 1.5)^{2} - (2 - 1.5)^{2}]

           = 11.25

As,

          W_{f} = u_{1} + u_{2} + \frac{1}{2}mv^{2}

          \frac{1}{2}mv^{2} = W_{f} - u_{1} - u_{2}  

                   = 64.95 J - 29.4 - 11.25

                   = 24.3

              v^{2} = \frac{24.3 \times 2}{2}

                  v = 4.92 m/s

Therefore, we can conclude that relative velocity at point B is 4.92 m/s.  

7 0
3 years ago
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