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DIA [1.3K]
3 years ago
15

a device employing a lens, shutter, and persistent light source that projects images from glass slides onto a flat white wall or

cloth drape hung in the dark is _______
Physics
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

The answer is a projector

Explanation:

A projector is an output device that projects an image onto a large surface, such as a white screen or wall. It may be used an alternative to a monitor or television when showing video or images to a large group of people, mostly at functions, events, seminars, presentations.

seraphim [82]3 years ago
6 0

A device employing a lens, shutter, and persistent light source that projects images from glass slides onto a flat white wall or cloth drape hung in the dark is image projection began with the MAGIC LANTERN

<h3><u>Explanation:</u></h3>

The magic lantern works on the sliding runner technology. The image can be made larger in size and can be projected with the help of an optical device. When the technology of motion toy become older, this magic lantern is the modernized version of the motion toy technology. The modernization of the magic lantern was as an alternative of to motion-toy technology.

The photos and images that are taken can be increased in the size and projection can be made. These images can be enlarged in size by the help of a photographic images. this helps in image and also in taking photographs. This photographic image can be attached with Magic lantern. A long slide of glass helps in projecting the image on the walls or cloth drapes using magic lantern. This gives life to Shadows.

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Explain how columns can be used and set up to increase the effectiveness of business documents.
Usimov [2.4K]
You can put the name of the product and the price and add another column and add all of your expenses<span />
3 0
3 years ago
In one experiment, the students allow the block to oscillate after stretching the spring a distance A. If the potential energy s
atroni [7]

Answer:

    K = m g (A - A2)

Explanation:

In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential

         Em = U₀ = m g A

For when the system is at an ele

Elongation A2 less than A, energy has two parts

        Em = K + U₂

       K = Em –U₂

We substitute

     K = m g A - m gA2

    K = m g (A - A2)

3 0
3 years ago
Read 2 more answers
Two identical point charges are 3.00 cm apart. find the charge on each of them if the force or repulsion is 4.00 x 10^-7. (Use C
DanielleElmas [232]

Answer:

Charge on each is 2 x 10⁻¹⁰.

Explanation:

We know that Force between two point charges is given b the Coulomb's law as:

F = kq₁q₂/r^2

k = 9 x 10^9

r = 3.00 cm

= 0.03 m

q₁ = q₂

F = 4.00 x 10^-7

Rearranging the formula, we get:

F = k q²/r²

q² = Fr²/k

q² = 4 x 10⁻⁷ x 0.03²/(9x10⁹)

q² = 4 x 10⁻²⁰

q = 2 x 10⁻¹⁰

As there is force of repulsion between the charges, the charges must be both positive or both negative.

3 0
3 years ago
determine the pressure exerted on the surface of a submarine cruising 175 ft below the free surface of the sea. assume that the
Alenkasestr [34]

Answer:

92.81 psia.

Explanation:

The density of water by multiplying its specific gravity by the density of sea water.

SG = density of sea water/density of water

ρ = SG x ρw

1 kg/m3 = 62.4 lbm/ft^3

= 1.03 * 62.4

= 64.27lbm/ft^3.

The absolute pressure at 175 ft below sea level as this is the location of the submarine.

P = Patm +ρgh

= 14.7 + 64.27 * 32.2 * 175

Converting to pound force square inch,

= 14.7 + 64.27 * (32.2ft/s^2) * (175ft) * (1lbf/32.2lbm⋅ft/s^2) * (1ft^2/144in^2 )

= 14.7 + 78.11 psia

= 92.81 psia.

8 0
3 years ago
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This
vova2212 [387]

Answer:

1.554\times 10^{32}\ \text{kg}

Explanation:

M = Mass of each star

T = Time period = 15.5 days

v = Orbital velocity = 230 km/s

G = Gravitational constant = 6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2

Radius of orbit is given by

R=\dfrac{vT}{2\pi}

We have the relation

\dfrac{Mv^2}{R}=\dfrac{GM^2}{(2R)^2}\\\Rightarrow M=\dfrac{4Rv^2}{G}\\\Rightarrow M=\dfrac{4\dfrac{vT}{2\pi}v^2}{G}\\\Rightarrow M=\dfrac{2v^3T}{\pi G}\\\Rightarrow M=\dfrac{2\times 230000^3\times 15.5\times 24\times 60\times 60}{\pi\times 6.674\times 10^{-11}}\\\Rightarrow M=1.554\times 10^{32}\ \text{kg}

The mass of each star is 1.554\times 10^{32}\ \text{kg}

6 0
3 years ago
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