Answer:
<em>The non resonance frequency of the generator is = 1201.79 Hz</em>
Explanation:
At resonance,
f₀ = 1/2π√LC..................... Equation 1
Where f₀ = resonance frequency, L = inductance, C = capacitance
making LC the subject of the equation
LC = 1/4πf₀²..................... Equation 2
<em>Given: </em>f₀ = 225 Hz, and π = 3.143
<em>Substituting these values into equation 2,</em>
LC = 1/(4×3.143²×225²)
LC = 1/2000385.9
LC = 5×10⁻⁷
If the ratio of capacitive reactance to inductive reactance = 5.36
1/2πfC/2πfL = 5.36
1/4π²f²LC = 5.36
Where f = frequency of the non resonant
making f the subject of the equation
f = 5.36/2π√LC ............. Equation 3
Substituting the value of LC = 5×10⁻⁷ into equation 3
f = 5.36/2×3.143√(5×10⁻⁷)
f = 5.36/(6.286×0.00071)
f = 5.36/0.00446
<em>f = 1201.79 Hz</em>
<em>Thus the non resonant frequency of the generator is = 1201.79 Hz</em>
Answer:
a) B = 10⁻¹ r
, b) B = 4 10⁻⁹ / r
, c) B=0
Explanation:
For this exercise let's use Ampere's law
∫ B. ds = μ₀ I
Where I is the current locked in the path. Let's take a closed path as a circle
ds = 2π dr
B 2π r = μ₀ I
B = μ₀ I / 2μ₀ r
Let's analyze several cases
a) r <Rw
Since the radius of the circumference is less than that of the wire, the current is less, let's use the concept of current density
j = I / A
For this case
j = I /π Rw² = I’/π r²
I’= I r² / Rw²
The magnetic field is
B = (μ₀/ 2π) r²/Rw² 1 / r
B = (μ₀ / 2π) r / Rw²
calculate
B = 4π 10⁻⁷ /2π r / 0.002²
B = 10⁻¹ r
b) in field between Rw <r <Rs
In this case the current enclosed in the total current
I = 0.02 A
B = μ₀/ 2π I / r
B = 4π 10⁻⁷ / 2π 0.02 / r
B = 4 10⁻⁹ / r
c) the field outside the coaxial Rs <r
In this case the waxed current is zero, so
B = 0
Answer:
98%
Explanation:
Given parameters
Mass of motor = 10kg
Height = 2m
Time = 2s
Power input = 100w
Unknown
Efficiency = ?
Solution
Efficiency is the percentage of the power output to the power input.
Power is the rate at which work is done.
Power output = mass x g x height / time
g is the acceleration due to gravity
Power output = 10x 2 x 9.8 / 2 = 98W
Efficiency = power output/ power input x 100
Efficiency = 98/100 x 100 = 98%
Answer: 750 N
Explanation:
The net force is 1200 - 450 = 750 N
As we are told the speed is constant, then this force must be increasing the car's potential energy by climbing a hill.
F = mgsinθ
If we knew the car mass, we could find the hill slope angle.
If we knew the hill slope angle, we could find the car mass.
More protons than electron
