Answer:



Explanation:
From the question we are told that
The length of the string is 
The mass of the string is 
The distance from the bridge to the support post 
The tension is 
Generally the frequency is mathematically represented as
![v = \frac{n}{2 * L } [\sqrt{ \frac{T}{\mu} } ]](https://tex.z-dn.net/?f=v%20%20%3D%20%20%5Cfrac%7Bn%7D%7B2%20%2A%20L%20%7D%20%20%5B%5Csqrt%7B%20%5Cfrac%7BT%7D%7B%5Cmu%7D%20%7D%20%5D)
Where n is and integer that defines that overtones
i.e n = 1 is for fundamental frequency
n = 2 first overtone
n =3 second overtone
Also
is the linear density of the string which is mathematically represented as

=> 
=> 
So for n = 1
![v_1 = \frac{1}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]](https://tex.z-dn.net/?f=v_1%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%20%2A%20%200.62%20%7D%20%20%5B%5Csqrt%7B%20%5Cfrac%7B%20540%7D%7B0.003889%7D%20%7D%20%5D)

So for n = 2
![v_2 = \frac{2}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]](https://tex.z-dn.net/?f=v_2%20%20%3D%20%20%5Cfrac%7B2%7D%7B2%20%2A%20%200.62%20%7D%20%20%5B%5Csqrt%7B%20%5Cfrac%7B%20540%7D%7B0.003889%7D%20%7D%20%5D)

So for n = 3
![v_3 = \frac{3}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]](https://tex.z-dn.net/?f=v_3%20%20%3D%20%20%5Cfrac%7B3%7D%7B2%20%2A%20%200.62%20%7D%20%20%5B%5Csqrt%7B%20%5Cfrac%7B%20540%7D%7B0.003889%7D%20%7D%20%5D)

<u>Answer:</u>
1. A graph is defined as <em>" A Diagram represents a system of connections or interrelations among two or more things by a number of different dots, lines etc".</em>
2. In simple words <em>"Graph is a representation of any object or a physical structure by dots, lines, etc.</em>
Answer: 3.41 s
Explanation:
Assuming the question is to find the time
the ball is in air, we can use the following equation:

Where:
is the final height of the ball
is the initial height of the ball
is the initial velocity of the ball
is the time the ball is in air
is the acceleration due to gravity

Then:


Multiplying both sides of the equation by -1 and rearranging:

At this point we have a quadratic equation of the form
, which can be solved with the following formula:
Where:
Substituting the known values:
Solving the equation and choosing the positive result we have:
This is the time the ball is in air
Answer:
the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²
Explanation:
Given the data in the question;
Sound power P = 26.0 W
Area of microphone A = 1.00 cm²
Radius r = 53.0 m
sound intensity at the position of the microphone = ?
Now, intensity at the position of the microphone can be determined using the following expression;
= P / 4πr²
We substitute
= 26.0 / ( 4 × π × (53.0 )² )
= 26.0 / ( 4 × π × 2809 )
= 26.0 / 35298.935
= 26.0 / ( 4 × π × (53.0 )² )
= 0.000736566
= 7.4 × 10⁻⁴ W/m²
Therefore, the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²
Answer:
mass = 14
Explanation:
equation ; p = m / v
2 = m / 7
to get the m, your variable, by itself you would multiply 7 onto the other side of the equation, getting this;
2 * 7 = m
and 2 * 7 = 14, therefore m = 14, so your mass would be 14!
Hope this helps!