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vivado [14]
3 years ago
11

Someone solve this please...........​

Physics
2 answers:
Natali [406]3 years ago
4 0

Answer:

The answer is 4x³ + 6x²

<u>-TheUnknownScientist</u><u> 72</u>

Kryger [21]3 years ago
4 0

Answer:

hi I was on school yah ...

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PLEASE ANSWER ASAP!!! ITS DUE IN 10 MINUTES!!!!!!
forsale [732]

Explanation:

2. Aerobic exercise. ...

Strength building. ...

Balance Training. ...

Endurance. ...

Flexibility. ...

Moderate intensity exercise. ...

Vigorous exercise.

3.Brisk walking.

Running.

Jogging

Bear crawls.

Swimming.

Water aerobics.

Cycling/bicycling.

4. Running or Jogging. ...

Outdoor Cycling. ...

Walking.

5. The type of exercise to build muscle is strength training, although cardiovascular activity can also provide benefits.

Hope it helps..

5 0
3 years ago
What is the frequency of a wave?
Paladinen [302]
The answer should be the number, or amount, of cycles that occur in a given time. Frequency is basically Hertz. Frequency is the number of waves that pass through a certain point every second. I hope that I was able to answer your question.
Peace out!

- Hershy103
6 0
3 years ago
Read 2 more answers
An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 19 m lower vert
cupoosta [38]

Answer:

The compression in the spring is 5.88 meters.                

Explanation:

Given that,

Mass of the car, m = 39000 kg

Height of the car, h = 19 m

Spring constant of the spring, k=4.2\times 10^5\ N/m

We need to find the compression in the spring in stopping the ore car. It can be done by balancing loss in gravitational potential energy and the increase in elastic energy. So,

mgh=\dfrac{1}{2}kx^2

x is the compression in spring

x=\sqrt{\dfrac{2mgh}{k}} \\\\x=\sqrt{\dfrac{2\times 39000\times 19\times 9.8}{4.2\times 10^5}} \\\\x=5.88\ m

So, the compression in the spring is 5.88 meters.                                                                                                                  

6 0
3 years ago
Everyone can be hypnotized?
MAXImum [283]

Answer:

false

Explanation:

8 0
2 years ago
A 16 g piece of Styrofoam carries a net charge of -8.6 µC and floats above the center of a large horizontal sheet of plastic tha
PilotLPTM [1.2K]

Answer:

the charge per unit area on the plastic sheet is - 3.23 x 10⁻⁷ C/m²

Explanation:

given information:

styrofoam mass, m = 16 g = 0.016 kg

net charge, q = - 8.6 μC

to calculate the charge per unit area on the plastic sheet, we can use the following equation:

F_{e} = mg

where

F_{e} = the force between the electric field

m = mass

g = gravitational force

F_{e} =qE

where

q = charge

E = electric field

and

E = σ/2ε₀

where

ε₀ = permitivity

thus

F_{e} =qE

mg = qσ/2ε₀

σ = (2mg ε₀)/q

  = 2 (0.016) (9.8)  (8.85 x 10⁻¹²)/( - 8.6 x 10⁻⁶)

  = - 3.23 x 10⁻⁷ C/m²

8 0
3 years ago
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