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3 years ago

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Chemistry

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tekilochka [14]3 years ago

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What is the difference between a heterogeneous mixture and homogeneous mixture?

Fiesta28 [93]

A homogeneous mixture has the same uniform appearance and composition throughout

A heterogeneous mixture consists of visibly different substances or phases.

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How many oxygen atoms are in a representative particle of each substance?

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NH4NO3 b) C8H8O4 c) O3 d) C3H5(NO3)3

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Which correctly lists the types of matter, in terms of their atoms, in order from least tightly packed to most tightly packed? s

alukav5142 [94]

Answer:

gas, liquid, solid

Explanation:

As you go from gas to solid, the atoms get closer together and the kinetic energy decreases.

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3 years ago

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A solid sample of Zinc Hydroxide is added to 0.350 L of 0.500 M aqueous Hydrogen Bromide. The solution that remains is still aci

Iteru [2.4K]

Answer:

6.499 g

Explanation:

One part of the aqueous HBr reacted with Zinc Hydroxide following the reaction:

Zn(OH)₂ + 2HBr → ZnBr₂ + 2H₂O

And the remaining HBr reacted with NaOH:

NaOH + HBr → NaBr + H₂O

First we calculate how many HBr moles remained after reacting with Zn(OH)₂. That number equals the number of NaOH moles used in the titration:

0.500 M * 88.5 mL = 44.25 mmol NaOH = mmol HBr

Now we calculate how many moles of HBr reacted with Zn(OH)₂:

Originally there were (350 mL * 0.500 M) 175 mmol HBr

175 mmol - 44.25 mmol = 130.75 mmol HBr

Then we convert those 130.75 mmoles of HBr to the Zn(OH)₂ moles they reacted with:

130.75 mmol HBr * $\frac{1mmolZn(OH)_{2}}{2mmolHBr}$ = 65.375 mmol Zn(OH)₂.

Finally we convert Zn(OH)₂ moles to grams:

65.375 mmol Zn(OH)₂ * 99.424 mg/mmol = 6499.8 mg Zn(OH)₂

6499.8 mg Zn(OH)₂ / 1000 = 6.499 g

7 0

3 years ago

The empirical formula of pyrogallol is C2H2O. Its molar mass is 126 g mol-1. What is the molecular formula?C4H4O2C2H6O3C6H6O3C2H

VARVARA [1.3K]

Answer:

The molecular formula of pyrogallol is: C6H6O3

Explanation:

Step 1: Data given

Empirical formula of pyrogallol is C2H2O

Molar mass of pyrogallol = 126 g/mol

Molar mass of Carbon (C) = 12 g/mol

Molar mass of hydrogen (H) = 1.01 g/mol

Molar mass of oxygen (O) = 16 g/mol

Step 2: Calculate molar mass of the empirical formula

2*12 + 2*1+ 16 = 42 g/mol

Step 3: Calculate the molecular formula

To find the molecular formule , we should multiply the empirical formula by n

n can be found by dividing molar mass of pyrogallol by the molar mass of the empirical formula

n = 126 g/mol / 42 g/mol ≈ 3

We should mulitply the empirica lformula by 3

3*(C2H2O) gives C6H6O3

if we calculate the molar mass now:

6*12 +6*1 + 3*16 = 126 g/mol

The molecular formula of pyrogallol is: C6H6O3

6 0

3 years ago