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4 years ago

Will give brainliest if you show work and have the right answer :)

Chemistry

2 answers:

katrin2010 [14]4 years ago

5 0

<u>Answer:</u> The mass of water reacted is 36 grams

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The chemical equation for the reaction of sulfur dioxide with bromine and water follows:

$SO_2+Br_2+2H_2O\rightarrow 2HBr+H_2SO_4$

Let the mass of water be 'x' grams

We are given:

Mass of sulfur dioxide = 64.1 grams

Mass of bromine = 159.9 grams

Mass of hydrogen bromide = 161.9 grams

Mass of sulfuric acid = 98.1 grams

Total mass on reactant side = 64.1 + 159.9 + x = 224 + x

Total mass on product side = 161.9 + 98.1 = 260 g

So, by applying law of conservation of mass, we get:

$224+x=260\\\\x=(260-224)=36g$

Hence, the mass of water reacted is 36 grams.

suter [353]4 years ago

4 0

Answer:

The answer to your question is:

a) 36 g of water

Explanation:

MW SO₂ = 32 + 32 = 64 g

MW Br = 80 g

MW H₂O = 18 g

MW HBr = 81 g

MW H₂SO₄ = 98

Balanced reaction:

SO₂ + 2Br + 2H₂O ⇒ 2HBr + H₂SO₄

64g 2(80) 2(18) 2(81) 98

64.1 159.9 161.9 98.1

Rule of three with Br and H2O

160 g ---------------- 36 g

160 ------------------- x

x = 160(36)/160 = 36 g oh water

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kotykmax [81]

Answer:

Balanced reaction: $3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

S is oxidized and N is reduced.

$NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

Explanation:

Reaction: $ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO$

$\Rightarrow$ Oxidation: $ZnS\rightarrow Zn^{2+}+S$

Balance charge: $ZnS-2e^{-}\rightarrow Zn^{2+}+S$ ...............(1)

$\Rightarrow$ Reduction: $NO_{3}^{-}\rightarrow NO$

Balance H and O in acidic medium : $NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O$

Balance charge: $NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O$ ...............(2)

[ $3\times$ Equation-(1)] + [ $2\times$ Equation-(2)]:

$3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.

Oxidation number of N decreases from (+5) to (+2) for the conversion of $NO_{3}^{-}$ to NO. Therefore N is reduced.

$NO_{3}^{-}$ consumes electron from ZnS. Therefore $NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

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4 years ago

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How many N2 molecules would exist in 500g of water at 20C?

tankabanditka [31]

We have to know the number of molecules present in 500 g of water.

The answer is: zero molecules present in 500g of water.

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3 years ago

Chloroform has a density of 1.5 g/ml. What the mass of 10.0 ml of Chloroform?

8090 [49]

Answer:

The answer is 15 g

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The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

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We have

mass = 1.5 × 10

We have the final answer as

Hope this helps you

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3 years ago