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3 years ago

13

Why could the amount of available freshwater decrease in an area?

1 answer:

lesya692 [45]3 years ago

8 0

Answer:

In many areas of the United States, the demand for freshwater is likely to increase while supplies decrease due, in part, to a changing climate. ... As warmer temperatures increase the demand for water, the amount of freshwater available may decline and increase competition for water resources in some areas.

Explanation:

I hope this helps!

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Balance the following redox equation, identifying the element oxidized and the element reduced. Show all of the work used to sol

hodyreva [135]

The given equation is,

$Ag(s) + CN^{-}(aq) + O_{2}(aq) --> [Ag(CN)_{2}]^{-} (aq) + H_{2}O(l)$

3 0

3 years ago

What is the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm?

Volgvan

Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

Explanation:

Given: $V_{1}$ = 61 L, $T_{1}$ = 183 K, $P_{1}$ = 0.60 atm

At STP, the value of pressure is 1 atm and temperature is 273.15 K.

Now, formula used to calculate the new volume is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{0.60 atm \times 61 L}{183 K} = \frac{1 atm \times V_{2}}{273.15 K}\\V_{2} = 54.63 L$

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

4 0

2 years ago

How many moles of O2 should be supplied to burn 1.82 mol of C3H8 (propane) molecules In a camping stove?

pashok25 [27]

C3H8 + 5O2 ------> 3CO2 + 4H2O

from reaction 1 mol 5 mol

given 1.82 mol x mol

x=(1.82*5)/1 = 9.10 mol CO2

4 0

3 years ago

A compound with a molar mass of 102.133 g/mol contains an element with a subscript of 5 . the element is 58.80 g per 100.0 g com

VLD [36.1K]

Answer:

12.0108408

Explanation:

Denote the element with a letter like say X. Since it has a subscript of 5, then, X5.

Molecular mass=102.133g/mol.

% of X in compound =58.8/100

=0.588

Mass of X in the compound = 0.588*102.133 ( the % of X in compound * molar mass of compound)

= 60.054204

X5=60.054204

Then element X has a mass of 60.054204/5=12.0108408

6 0

3 years ago

What are some examples of chemical weathering(select all that apply):

ASHA 777 [7]

Answer:

reactions between air, water and minerals, chemicals in rain water

4 0

2 years ago

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