The net charge on the structure as shown in the question is -1.
<h3>What is a charged specie?</h3>
We say that a specie is charged if the specie has an excess of positive or negative charge. An excess of the positive charge means that the substance is positively charged while an excess if the negative charge simply means that the object is negative charged.
When we have a chemical structure as we have seen, it is possible that the structure as we have it could have a net charge. The net charge that the structure has can be deduced by looking at the formal charges that are carried by all the atoms that we have in the system.
The charge as we can see that is on the central atom of the molecule is the -1 charge hence this is the charge that is carried overall by the molecule.
If we then look at the structure as we can see, we can see that there is a charge of negative one that is attached to the atom of chlorine as is clearly visible and obvious from the image attached to the question.
Learn more about net charge:brainly.com/question/12708636
#SPJ1
I’m dgsgegegstdgstsffsrddgffddddsdgddffcffffffffdd
Valency is the number of electrons present in the outermost shell.
Answer to Diethyl ether can<span> be made from </span>ethanol<span>. The </span>reaction<span> is 2C2H5OH(</span>l) ----> (C2H5)2 O(l<span>) + </span>H2O(l<span>) The </span>percent yield<span> of diet...</span>
The reaction mixture of problem 1 includes <span>10mL of 4.0 M acetone = 10 mL 1.0 M HCl = 10 mL 0.0050 M I2 = 20 mL H2O. if this is true then the procedure is the following:
In order to find the total volume of reaction then you need to do like this:
</span><span>V = 10 mL + 10 mL + 10 mL + 20 mL = 50 mL </span>
<span>[I2]o = (0.005 mol I2 / 1 L I2 solution) (10 mL I2 solution) / 50 mL = 0.001 M </span>
<span>To first order, the reaction rate is 0.001 M / 230 s = 4,3 e-6 M/s
Then if you want to find the rate yoe need to use the following formula:
</span><span> k [CO(CH3)2]^a [I2]^b [HCl]^c
</span>So: <span>4,3 e-6 = k (4 M * 10 mL / 50 mL)^a (1e-3 M)^b (1 M * 10 mL / 50 mL)^c
</span>
