Question

A gas has a pressure of 410 atm and a volume of 32 L. At what pressure would the volume of the gas change to 28L?

Answer 1

Answer:

At 468.57 atm pressure the gas volume would change to 28 L.

Explanation:

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant.

This law can be expressed mathematically as:

P · V = k

where P is pressure, V is volume and k is a constant.

This formula can be used to determine the change in pressure or volume during an isothermal transformation (i.e. the temperature is constant) as follows:

P1 · V1 = P2 · V2

In this case,

• P1= 410 atm
• V1= 32 L
• P2= ?
• V2= 28 L

Replacing:

410 atm*32L= P2*28 L

Solving:

$P2=\frac{410 atm*32 L}{28L}$

P2=468.57 atm

At 468.57 atm pressure the gas volume would change to 28 L.