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fgiga [73]
2 years ago
11

Explain how vectors differ from scalars.​

Physics
1 answer:
s344n2d4d5 [400]2 years ago
7 0

Answer:

Vectors are fully described by magnitude and direction while scalars are fully described by magnititude/ size only

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A slit has a width of W1 = 4.4 × 10-6 m. When light with a wavelength of λ1 = 487 nm passes through this slit, the width of the
Vitek1552 [10]

Answer:

The width of the central bright fringe on the screen is observed to be unchanged is 4.48*10^{-6}m

Explanation:

To solve the problem it is necessary to apply the concepts related to interference from two sources. Destructive interference produces the dark fringes.  Dark fringes in the diffraction pattern of a single slit are found at angles θ for which

w sin\theta = m\lambda

Where,

w = width

\lambda =wavelength

m is an integer, m = 1, 2, 3...

We here know that as sin\theta as w are constant, then

\frac{w_1}{\lambda_1} = \frac{w_2}{\lambda_2}

We need to find w_2, then

w_2 = \frac{w_1}{\lambda_1}\lambda_2

Replacing with our values:

w_2 = \frac{4.4*10^{-6}}{487}496

w_2 = 4.48*10^{-6}m

Therefore the width of the central bright fringe on the screen is observed to be unchanged is 4.48*10^{-6}m

3 0
3 years ago
PLEAS HELP.
koban [17]

<span>A: put an atom on a poster in the exhibit
     Good luck.  The poster itself is made of trillions of trillions of trillions
     of atoms.  You could not see the extra one any easier than you could
     see the ones that are already there, and even if you could, it would be
     lost in the crowd.
 
B: use a life size drawing of an atom
     Good luck.  Nobody has ever seen an atom.  Atoms are too small
     to see.  That's a big part of the reason that nobody knew they exist
     until less than 200 years ago.

D: set up a microscope so that visitors can view atoms
     Good luck.  Atoms are way too small to see with a microscope.

</span><span><span>C: Display a large three dimensional model of an atom.
    </span> </span>Finally !  A suggestion that makes sense.
     If something is too big or too small to see, show a model of it
         that's just the right size to see.

8 0
3 years ago
A 5.0 cm object is 12.0 cm from a concave mirror that has a focal length of 24.0 cm. The distance between the image and the mirr
MA_775_DIABLO [31]

Answer:

The answer is 24cm

Explanation:

This problem bothers on the curved mirrors, a concave type

Given data

Object height h= 5cm

Object distance = 12cm

Focal length f=24cm

Let the image distance be v=?

Applying the formula we have

1/v +1/u= 1/f

Substituting our given data

1/v+1/12=1/24

1/v=1/24-1/12

1/v=1-2/24

1/v=-1/24

v= - 24cm

This implies that the image is on the same side as the object and it is real

7 0
3 years ago
Read 2 more answers
What simple machine can be described as a shaft that is attached to the center of a wheel?
charle [14.2K]
"Wheel & Axle" <span>can be described as a shaft that is attached to the center of a wheel

Hope this helps!</span>
4 0
3 years ago
Can someone explain to me what potential difference is? Simple answers are always better! P.s : Last time my electricity questio
Artyom0805 [142]
<span>the difference of electrical potential between two points. hope this helps</span>
3 0
3 years ago
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