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adoni [48]
3 years ago
12

Question 2 of 5 Which two statements are true for both compounds and mixtures? A. They can be separated into two or more element

s. B. Their particles all have the same chemical formula. C. Their particles are held together by chemical bonds. D. They are made up of more than one type of atom.​
Physics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

Answer:

D and A

I'm not sure about A lol

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How much power does device use that is plugged into an outlet with a voltage difference of 150 V if the current is 15 A? Show me
Alexeev081 [22]

Answer:

Power used = VI

= 150 x 15

= 2250 W

Hope this helps!

5 0
3 years ago
Read 2 more answers
What happens in a cloud to cause electrons to move from some particles to others?
vova2212 [387]

Answer:

Air molecules and suspended water droplets collide as they swirl around in the clouds. Warmer air and water droplets rise, carrying charges with them. The result is an excess of positive charge near the cloud tops, and an excess of negative charge in the bottom layers of the clouds.

they are knocked off some ice and added to other ice as they crash past each other

Explanation:

6 0
3 years ago
Two spheres A and B of negligible dimensions and masses 1 kg and √3 kg respectively, are supported on the smooth circular surfac
alexdok [17]

Answer:

α = π/3

β = π/6

Explanation:

Use arc length equation to find the sum of the angles.

s = rθ

π/20 m = (0.1 m) (α + β)

π/2 = α + β

Draw a free body diagram for each sphere.  Both spheres have three forces acting on them:

Weight force mg pulling down,

Normal force N pushing perpendicular to the surface,

and tension force T pulling tangential to the surface.

Sum of forces on A in the tangential direction:

∑F = ma

T − m₁g sin α = 0

T = m₁g sin α

Sum of forces on B in the tangential direction:

∑F = ma

T − m₂g sin β = 0

T = m₂g sin β

Substituting:

m₁g sin α = m₂g sin β

m₁ sin α = m₂ sin β

(1 kg) sin α = (√3 kg) sin (π/2 − α)

1 sin α = √3 cos α

tan α = √3

α = π/3

β = π/6

4 0
4 years ago
A sled of mass 15 kg slides across the ground with a friction force of 80.85 N. What is k between the sled and the ground?
Dvinal [7]
The expression for the frictional force between the sled and the ground is:
F=k m g
where k is the coefficient of friction, m is the mass of the object and g=9.81 m/s^2 is the gravitational acceleration.

The friction force in our problem is F=80.85 N. The mass of the object is m=15 kg. Re-arranging the formula, we can find the value of k:
k= \frac{F}{mg}= \frac{80.85 N}{(15 kg)(9.81 m/s^2)}=0.55
8 0
4 years ago
Read 2 more answers
A 1500-kg car traveling east with a speed of 25.0 m/s collides at an intersection with a 2500-kg van traveling north at a speed
IgorC [24]

Answer:

The direction and magnitude of velocity is 38.65° and 12.005 m/s

Explanation:

Given that,

Mass of car = 1500 kg

Speed of car = 25.0 m/s

Mass of van = 2500 kg

Speed of van =20.0 m/s

We need to calculate the velocity

Using conservation of energy

m_{c}u_{i}+m_{v}u_{i}=(m_{c}+m_{v})v_{f}

1500(25i+0j)+2500(0+20j)=4000(v_{f})

v_{f}=\dfrac{1500\times25}{4000}i+\dfrac{1500\times20}{4000}j

v_{f}=9.375 i+7.5 j

The magnitude of velocity

|v_{f}|=\sqrt{(9.375)^2+(7.5)^2}

|v_{f}|=12.005\ m/s

We need to calculate the direction

\tan\theta=\dfrac{coefficient\ of\ j}{coefficient\ of\ i}

\tan\theta=\dfrac{7.5}{9.375}

\theta=\tan^{-1}0.8

\theta=38.65^{\circ}

Hence, The direction and magnitude of velocity is 38.65° and 12.005 m/s.

3 0
4 years ago
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