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shusha [124]
3 years ago
12

One root of f(x)=x^3-4x^2-20x+48 is x = 6. What are all the factors of the function? Use the Remainder Theorem.

Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

(x - 6)(x + 4)(x - 2)

Step-by-step explanation:

since x = 6 is a root then (x - 6) is a factor

x³ - 4x² - 20x + 48 ÷ (x - 6)

= (x - 6)(x² + 2x - 8)

= (x - 6)(x + 4)(x - 2) ← factors of f(x)

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PLEASE HELP!<br><br><br> put integers in order least to greatest 3, -2, -5.
stiks02 [169]

Answer:

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4 years ago
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write the equation of a line that passes through the points (5, -7) and is perpendicular to the line -2x + 6y = -4
VashaNatasha [74]

Answer:

y= -3x + 8

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Put -2x + 6y = -4 into slope-interceltp form

Take the negative reciprocal of the slope.

Use this reciprocal in point-slope form

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= y= -3x + 8

<em>(EDITED)</em> Steps:

2x+6y = -4

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y= 1/3x + 2/3

if two lines are perpendicular,

m1 * m2 + -1

1/3 * m2 = -1

m2 = -3

the line perpendicular to this line is

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so,

-7 = -3. (5) +k

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∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is

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Nadusha1986 [10]
\bf \begin{cases}&#10;\quad3x+2y=-9\\&#10;-10x+5y=-5&#10;\end{cases}

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so... let's see, we have 2y and 5y, both positive
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so.. if we multiply 2y by -5/2, we'll end up with -5y

well, let's multiply that first equation then by -5/2

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so.. now we know x = 1.... so let's plug that in  say hmmm 2nd equation

\bf -10(1)+5y=-5\implies -10+5y=-5\implies 5y=5\implies\boxed{ y=1}
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4 years ago
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