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denis23 [38]
3 years ago
15

If an object is launched at 40 degrees what other angle will give you the same range

Physics
1 answer:
pochemuha3 years ago
7 0

Answer:

50 degrees

Explanation:

complimentary angles will give you the same range

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Sav [38]

Answer:

65 Newtons

Explanation:

4 0
3 years ago
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A 243 mL cup of whole milk contains about 45 mg of cholesterol. Express the cholesterol concentration of the milk in kilograms p
timama [110]

Answer: 0.1851 \frac{kg}{m^{3}}

Explanation:

We have this concentration in units of mg/ml:

\frac{45 mg}{243 ml}

And we need to express it in kg/m^{3}, knowing:

1 ml= 1 cm^{3}

1 m^{3}= (100 cm) ^{3}

1g = 1000 mg

1 kg = 1000 g

Hence:

\frac{45 mg}{243 cm^{3}} \frac{1 g}{1000 mg} \frac{1 kg}{1000 g} \frac{(100 cm) ^{3}}{1 m^{3}}=0.1851 \frac{kg}{m^{3}}

5 0
4 years ago
The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.11 mm is given by J = (3.
oksano4ka [1.4K]

Answer:

i = 2.84 \times 10^{-3} A

Explanation:

As we know that current density is ratio of current and area of the crossection

now we have

J = \frac{di}{dA}

so the current through the wire is given as

i = \int J dA

now we have

i = \int_{0.921R}^R J dA

here we have

J = (3.25 \times 10^8)r^2

now plug in the values in above equation

i = \int_{0.921R}^R (3.25 \times 10^8)r^2 2\pi r dr

now we have

i = \int_{0.921R}^R 2\pi (3.25 \times 10^8)r^3 dr

i = (2.04 \times 10^9) \frac{r^4}{4}

now plug in both limits as mentioned

i = (2.04 \times 10^9)(\frac{R^4}{4} - \frac{(0.921R)^4}{4})

i = (2.04\times 10^9)(0.07 R^4)

here R = 2.11 mm

i = (2.04 \times 10^9)(0.07 (2.11 \times 10^{-3})^4)

i = 2.84 \times 10^{-3} A

8 0
3 years ago
A monkey runs 10\,\text m10m10, start text, m, end text to the right and then climbs 10 \,\text m10m10, start text, m, end text
Eduardwww [97]

Answer:

45º

Explanation:

6 0
3 years ago
Given a force of 90 N and a acceleration of 30 m/s/s, what is the object’s mass?
vladimir2022 [97]
The object’s mass is 3
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3 years ago
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