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kati45 [8]
4 years ago
9

(Please help!!!Will give brainlest!) What is the product of 1/2x - 1/4 and 5x^2 - 2x + 6 ? Write your answer in standard form. C

an someone please help me with this? I understand how to multiply polynomials and such but this ones hard for me? Please explain.
Mathematics
2 answers:
AlekseyPX4 years ago
4 0

The product of 1/2x - 1/4 and 5x^2 - 2x + 6 is 5/2x^3 – 9/4x^2 + 7/2x – 3/2

(a) (1/2x - 1/4) (5x^2 – 2x + 6)  

5/2x^3 – 5/4x^2 – 4/4x^2 + 2/4x +6/2x-6/4  

(I used 4/4 because it benefits me more when I visually see it)  

5/2x^3 -9/4x^2 + 14/4x – 6/4  

5/2x^3 – 9/4x^2 + 7/2x – 3/2

(b) No, because with the first part of the problem, the negative goes to ½ instead of 1/4x. When you find the product, instead of finding the exact same answer, you get 5/4x^3 – 3x^2 + 5/2x -3. The numbers when switched, change what they do. 1/4x just multiplies without a negative and ½ does with a negative.


slega [8]4 years ago
3 0
(\frac{1}{2} x -  \frac{1}{4})( 5x^{2} - 2x + 6)
\frac{5}{2} x^{3} -  x^{2} + 3x -  \frac{5}{4} x^{2} + \frac{1}{2}x -  \frac{3}{2}
\frac{5}{2} x^{3}  - \frac{9}{4} x^{2}  +  \frac{7}{2}x- \frac{3}{2}
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A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

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Step-by-step explanation:

Previous concepts

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Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

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Vesnalui [34]
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Mark brainliest please



Hope this helps you
7 0
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