Answer:
2.75 m/s^2
Explanation:
The airplane's acceleration on the runway was 2.75 m/s^2
We can find the acceleration by using the equation: a = (v-u)/t
where a is acceleration, v is final velocity, u is initial velocity, and t is time.
In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1
a = 2.75 m/s^2
Answer:
For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.
Explanation:
Hope this helps
Answer:
relates the electric field at points on a closed surface to the net charge enclosed by that surface.
Explanation:
Gauss Law states that overall electric flux of a closed surface is equivalent right to charge enclosed which is divided by the permittivity. In other words Gauss Law stress that
net electric flux that pass through an hypothetical closed surface is equivalent to overall electric charge present within that closed surface.
The Gauss law can be expressed mathematically as
ϕ = (Q/ϵ0)
Q = total charge within the surface,
ε0 = the electric constant
Answer:
Explanation:
Given
For first case
launch angle 
at highest point 
For second case
at highest Point velocity is 
as there is no acceleration in x direction therefore horizontal velocity is same
